我迷失了这个话题。我会试着解释一下我要做的事情: - 我的想法是,能够将jpg文件上传或保存到我的访问2010数据库,这个过程是由excel中的usign宏启动的。我在互联网上经常阅读,但说实话,我已经陷入困境,我无法找到一个例子。 我想使用ADO连接 我的想法是使用贴标签,这个标签会有所不同,我的意思是,我想用这些图片打印这些标签。
下面你可以看到我想做的事情。我迷路了,我得到错误,也许如果有人有一个例子我可以适应它,因为,我认为,我无法使用我拥有的那个。
程序如下:
Sub SUBIRIMAGEN() 'To save a file in a table as binary
Dim adoStream As Object
Dim adoCmd As Object
Dim strFilePath As String
Dim adoCon As Object
Const strServerName As String = "" 'Server Name
Set adoCon = CreateObject("ADODB.Connection")
Set adoStream = CreateObject("ADODB.Stream")
Set adoCmd = CreateObject("ADODB.Command")
strDBName = "database1.accdb"
strMyPath = ThisWorkbook.Path
strDB = strMyPath & "\" & strDBName
'Connect to a data source:
'For pre - MS Access 2007, .mdb files (viz. MS Access 97 up to MS Access 2003), use the Jet provider: "Microsoft.Jet.OLEDB.4.0". For Access 2007 (.accdb database) use the ACE Provider: "Microsoft.ACE.OLEDB.12.0". The ACE Provider can be used for both the Access .mdb & .accdb files.
'--Open Connection to SQL server
adoCon.CursorLocation = adUseClient
adoCon.Open ConnectionString:="Provider = Microsoft.ACE.OLEDB.12.0; data source=" & strDB
Rem adoCon.Open "Provider=SQLOLEDB;Data Source=" & strServerName & ";Initial Catalog = " & strDB & ";Integrated Security=SSPI;"
'----
strFilePath = "C:\Users\pc2\Downloads\frutossecosgranel.JPG" ' File to upload
adoStream.Type = adTypeBinary
adoStream.Open
adoStream.LoadFromFile strFilePath 'It fails if file is open
With adoCmd
.CommandText = "INSERT INTO table1 (id,attach) VALUES (?,?) " ' Query
.CommandType = adCmdText
'---adding parameters
.Parameters.Append .CreateParameter("@Id", adInteger, adParamInput, 0, 1)
.Parameters.Append .CreateParameter("@attach", adVarBinary, adParamInput, adoStream.Size, adoStream.Read)
'---
End With
adoCmd.ActiveConnection = adoCon
adoCmd.Execute
adoCon.Close
End Sub
答案 0 :(得分:0)
使用以下代码将图像附加到excel的数据库访问。
将此代码写入excel
根据需要修改常量
Private Sub AttachImage()
Const dbname = "c:\temp\Db.accdb"
Dim sql As String
Dim db As Database
Dim rst As Recordset2
Dim rstImage As Recordset2
Dim imageField As Field2
Dim path As String
Dim lnga As Integer
Dim lngkey As Long
path = "c:\temp\table.png"
'select the row to be attached by image
sql = "SELECT * FROM table2 WHERE ID = 1"
Set db = DBEngine.Workspaces(0).OpenDatabase(dbname)
Set rst = db.OpenRecordset(sql)
Set imageField = rst!Blob ' Blob is the field name to store attachment
Set rstImage = imageField.Value
rst.Edit
rstImage.AddNew
On Error Resume Next
rstImage!FileData.LoadFromFile path
If Err <> 0 Then
MsgBox "Error: " + Err.Description, vbInformation, path
Exit Sub
End If
rstImage.Update
rst.Update
Set rst = Nothing
Set db = Nothing
End Sub