Question

我有3 Thread.sleep(1000); s，我希望在1秒（1000毫升）后逐个显示。 find_hi-again无效。我不知道，完成任务后将显示三个JLabel（3秒后同时显示3个JLabel）。我该如何解决？定时器可以延迟吗？

Answer 1

你可以试试这个

  int delay = 1000; //milliseconds
  ActionListener taskPerformer = new ActionListener() {
      public void actionPerformed(ActionEvent evt) {
          //...Perform a task...
      }
  };
  new Timer(delay, taskPerformer).start();

您可以阅读更多Manually adding legend values in leaflet

Answer 2

以下是我对此的看法：

package demo.javase.swing;

import java.awt.Dimension;
import java.awt.FlowLayout;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import javax.swing.JButton;
import javax.swing.JFrame;
import javax.swing.JLabel;
import javax.swing.JPanel;
import javax.swing.Timer;

public class ThreeJLabelsDemo extends JPanel {

    private Timer timer;

    private JButton startButton;

    private int count;

    public ThreeJLabelsDemo() {
        super(new FlowLayout());

        startButton = new JButton("Add 3 JLabels");
        startButton.addActionListener(new ActionListener() {

            @Override
            public void actionPerformed(ActionEvent e) {
                startButton.setEnabled(false);
                timer.start();
            }

        });
        add(startButton);

        timer = new Timer(1000, new ActionListener() {

            @Override
            public void actionPerformed(ActionEvent e) {
                add(new JLabel("Label" + count++));
                revalidate();
                repaint();
                timer.stop();
                if (count < 3) {
                    timer.restart();
                } else {
                    startButton.setEnabled(true);
                    count = 0;
                }
            }

        });
    }

    private static void createAndShowGUI() {
        JFrame frame = new JFrame("Three JLabels Demo");
        frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
        frame.setContentPane(new ThreeJLabelsDemo());
        frame.setSize(new Dimension(640, 480));
        frame.setVisible(true);
    }

    public static void main(String[] args) {
        javax.swing.SwingUtilities.invokeLater(new Runnable() {

            @Override
            public void run() {
                createAndShowGUI();
            }

        });
    }

}

我相信在这种情况下，您必须使用javax.swing.Timer，因为Thread.sleep(long)会阻止该应用。

在java中延迟

2 个答案: