我尝试播放歌曲并将动态ID传递给控制器。但我尝试了这段代码。
<?php
$i = 1;
foreach ($view as $row)
{
echo "<tr>";
echo "<td>".$i."</td>";
echo "<td>"."<a href='<?php echo base_url();?>admin/play/$row->audio'".$row->audio."</a></td>";
$i++;
echo "</tr>";
}
?>
在检查元素锚时显示直接php代码而不是localhost / bla / bla /我该如何解决这个问题？我的控制器名称是播放，我想传递其特定名称的值。我的串联是正确的吗？
答案 0 :(得分：1)
你打开两次php标签。像这样：
http = require('http');
fs = require('fs');
server = http.createServer( function(req, res) {
console.dir(req.param);
if (req.method == 'POST') { //-- Here Process POST requests
console.log("POST");
var body = '';
req.on('data', function (data) {
body += data;
console.log("Partial body: " + body);
});
req.on('end', function () {
console.log("Body: " + body);
});
res.writeHead(200, {'Content-Type': 'text/html'});
res.end('post received');
}
else
{ //!!!----Here process HTML pages
console.log("GET");
//var html = '<html><body><form method="post" action="http://localhost:3000">Name: <input type="text" name="name" /><input type="submit" value="Submit" /></form></body>';
var html = fs.readFileSync('index.html');
res.writeHead(200, {'Content-Type': 'text/html'});
res.end(html);
}
});
port = 3000;
host = '127.0.0.1';
server.listen(port, host);
console.log('Listening at http://' + host + ':' + port);