从（String）=＆gt;获取（长，字符串）试试[（Long，String）]

Question

我有一个返回(String) => Try[(Long, String)]类型的方法，我希望获得(Long, String)。有什么建议吗？

我认为map / flatMap会有所帮助，但看起来却没有。

更新

def someMethod():(Long, String) = {
  val result: (String) => Try[(Long, String)] = someOperation()
  //Need to get (Long, String) from result
}

Answer 1

有几个选项

Alias /newfolder/ "C:/www/newfolder/"

<Directory "C:/www/newfolder">
    Options Indexes MultiViews
    AllowOverride AuthConfig
    Order allow,deny
    Allow from all
</Directory>

提供后备价值

val exceptional: Try[(Long, String)] = ???
val default: (Long, String) = (0, "")

处理异常，然后安全地exceptional.getOrElse(default)

get

或使用模式匹配

exceptional.recover { case exception => default }.get