Question

我在尝试加入Matlab中不同来源的代码时遇到了问题，我真的不知道如何处理它。基本上，我有一些Python代码用于从命令行调用的压缩算法，该算法本身使用子进程来运行并与编译为二进制文件的C ++代码进行通信。

Python中的函数（它是更大对象的一部分）如下所示：

system('./temp_script')

为了最大限度地减少移植问题，我决定通过系统命令完全间接地与Matlab集成，将脚本与所有组件放在一起并通过

运行它

cd /home/ben/Documents/MATLAB/StructureDiscovery/+sd/Lexis
python Lexis.py -f i /home/ben/Documents/MATLAB/StructureDiscovery/+sd/Lexis/aabb.txt >> /home/ben/Documents/MATLAB/StructureDiscovery/+sd/Lexis/lexis_results.txt

其中temp_script是可执行的，如下所示：

    Traceback (most recent call last):
  File "Lexis.py", line 762, in <module>
    g.GLexis(quietLog, rFlag, functionFlag, costWeight)
  File "Lexis.py", line 191, in GLexis
    (maximumRepeatGainValue, selectedRepeatOccs) = self.__retreiveMaximumGainRepeat(normalRepeatType, CostFunction.EdgeCost)
  File "Lexis.py", line 242, in __retreiveMaximumGainRepeat
    repeats = self.__extractRepeats(repeatClass)
  File "Lexis.py", line 302, in __extractRepeats
    process.stdin.write(' '.join(map(str,self.__concatenatedDAG)))
IOError: [Errno 32] Broken pipe

现在我在Ubuntu 16.04中运行它，从终端运行脚本。但是，从Matlab运行相同的脚本会给我带来错误

  File "Lexis.py", line 251, in __retreiveMaximumGainRepeat
    idx = map(int,repeatStats[2][1:-1].split(','))[0]
ValueError: invalid literal for int() with base 10: 'ersio'

或错误

    repeats = self.__extractRepeats(repeatClass)
    for r in repeats: #Extracting maximum repeat
        repeatStats = r.split()
        idx = map(int,repeatStats[2][1:-1].split(','))[0]

我无法弄清楚什么时候能得到哪一个。

repeatStats的相关片段是

import requests
from bs4 import BeautifulSoup
url = 'http://projects.chicagoreporter.com/settlements/search/cases'
source_code = requests.get(url)
plain_text = source_code.text
soup = BeautifulSoup(plain_text,"html.parser")
for link in soup.findAll('div',{'class':'case-payment'}):
    href = "http://projects.chicagoreporter.com/settlements/search/cases"
    title = link.string
    print(title)

我真的不知道Matlab通过系统调用某些内容并直接从终端调用它之间有什么不同，所以我不知道出了什么问题。在OSX 10.11上，完全相同的代码可以工作。

有没有人知道Matlab的系统命令的内部工作原理以及为什么它可能无法允许Python调用子进程？

任何帮助将不胜感激！

Answer 1

repeats = self.__extractRepeats(repeatClass)
for r in repeats: #Extracting maximum repeat
    repeatStats = r.split()
    idx = map(int,repeatStats[2][1:-1].split(','))[0]

假设你的repeatStats [2]是xersiox，10

然后，repeatStats [2] [1：-1]变为ersiox，1

然后，repeatStats [2] [1：-1] .split（＆＃39;，＆＃39;）会产生一个列表[＆＃39; ersio＆＃39;，＆＃39; 1＆＃39;]

您已将整个列表传递给整个语句

idx = map(int,repeatStats[2][1:-1].split(','))[0]
# it looks like this idx = map(int, ['ersio', '1'])[0]
# it picks the first item from the list, which is 'ersio', which does not have any numerical in that.

请尝试以下方法：

idx = map(int,repeatStats[2][1:-1].split(',')[1])[0]
# or provide an index of the item in the list, which has a number in it.

从Matlab调用的Python子进程失败

1 个答案: