Question

我需要执行一个简单的traceroute并将结果存储在列表中以获得更多功能。

我在网上发现了一些东西，有些人在python上使用完整的脚本，有些人使用子进程，我认为后者会更容易，所以我尝试了一个简单的脚本我找到了

代码：

from subprocess import Popen, PIPE
import sys

def tracer(host=None):
    p = Popen(['traceroute', host], stdout=PIPE)
    while True:
        try:
            line = p.stdout.readline()
            if not line:
                break
            print (line.rstrip())
        except:
            break

tracer('8.8.8.8')

但是我得到了一个孩子异常

>>> tracer('8.8.8.8')
Traceback (most recent call last):
  File "<console>", line 1, in <module>
  File "<console>", line 2, in tracer
  File "/usr/lib64/python2.7/subprocess.py", line 711, in __init__
    errread, errwrite)
  File "/usr/lib64/python2.7/subprocess.py", line 1327, in _execute_child
    raise child_exception
OSError: [Errno 2] No such file or directory
>>>

使用子进程是最简单的方法，还是应该使用脚本？

由于

Answer 1

from subprocess import Popen, PIPE
import sys

def tracer(host=None):
    p = Popen(['tracert', host], stdout=PIPE)
    while True:
        try:
            line = p.stdout.readline()
            if not line:
                break
            print (line.rstrip())
        except:
            break

tracer('8.8.8.8')```
had the same issue i changed once bit because the code was made for linux systems and you are using a windows system

Python - traceroute和存储结果

1 个答案: