Question

我目前有这个RequestMapping，我通过正则表达式使用验证：

 @RequestMapping(value = "/example/{id}", method = GET)
 public Response getExample(
         @PathVariable("id") String id,
         @RequestParam(value = "myParam", required = true) @Valid @Pattern(regexp = MY_REGEX) String myParamRequest,
         @RequestParam(value = "callback", required = false) String callback,
         @RequestHeader(value = "X-API-Key", required = true) @Valid @Pattern(regexp = SEGMENTS_REGEX) String apiKeyHeader) {

     // Stuff here...
 }

然而，正则表达还不够。相反，我想对标题属性进行一些自定义验证，即

if (!API_KEY_LIST.contains(apiKeyHeader)) {
    throw Exception();
}

这可能吗？

Answer 1

执行此操作的最佳方式IMO是使用自定义注释创建自定义HandlerMethodArgumentResolver，使用自定义注释@Segment：

public class SegmentHandlerMethodArgumentResolver implements HandlerMethodArgumentResolver {

    @Override
    public boolean supportsParameter(MethodParameter parameter) {
        return parameter.getParameterType().equals(String.class)
            && parameter.getParameterAnnotation(Segment.class);
    }

    @Override
    public Object resolveArgument(MethodParameter parameter, ModelAndViewContainer mavContainer, NativeWebRequest webRequest, WebDataBinderFactory binderFactory) throws Exception {
        String apiKey = webRequest.getHeader("X-API-Key");
        if (apiKey != null) {
            if (!API_KEY_LIST.contains(apiKey)) {
                throw new InvalidApiKeyException();
            }
            return apiKey;
        } else {
            return WebArgumentResolver.UNRESOLVED;
        }
    }
}

然后您的控制器签名如下所示：

@RequestMapping(value = "/example/{id}", method = GET)
 public Response getExample(
         @PathVariable("id") String id,
         @RequestParam(value = "myParam", required = true) @Valid @Pattern(regexp = MY_REGEX) String myParamRequest,
         @RequestParam(value = "callback", required = false) String callback,
         @Segment String apiKeyHeader) {

     // Stuff here...
 }

您将在WebMvcConfigurationAdapter中注册处理程序方法参数解析器：

@Configuration
public class MvcConfig extends WebMvcConfigurerAdapter {

    @Override
    public void addArgumentResolvers(List<HandlerMethodArgumentResolver> argumentResolvers) {
        argumentResolvers.add(segmentHandler());
    }

    @Bean
    public SegmentHandlerMethodArgumentResolver segmentHandler() {
        return new SegmentHandlerMethodArgumentResolver();
    }

}

Answer 2

1）手动检查

您可以注入HttpServletRequest并检查标题。

@RestController
public class HomeController {
    public ResponseEntity<String> test(HttpServletRequest request){
        if(request.getHeader("apiKeyHeader") == null){
            return new ResponseEntity<String>(HttpStatus.BAD_REQUEST);
        }
        return new ResponseEntity<String>(HttpStatus.OK);
    }
}

2）注入标题

@RequestMapping(value = "/test", method = RequestMethod.POST)
public ResponseEntity<String> test(@RequestHeader(value="myheader") String myheader){
    return new ResponseEntity<String>(HttpStatus.OK);
}

那将返回：

{
  "timestamp": 1469805110889,
  "status": 400,
  "error": "Bad Request",
  "exception": "org.springframework.web.bind.ServletRequestBindingException",
  "message": "Missing request header 'myheader' for method parameter of type String",
  "path": "/test"
}

如果标题丢失。

3）使用过滤器

如果要在多种方法中使用它，可以使用某些过滤器自动执行检查。在您的自定义过滤器中，只需获取标题（如方法1中所示），如果标题丢失，则只需响应400或任何您想要的内容。对于我来说，当你不使用控制器方法中的标题值并且只需要验证它是否存在时，这是有意义的。

@Bean
public FilterRegistrationBean someFilterRegistration() { 
    FilterRegistrationBean registration = new FilterRegistrationBean();
    registration.setFilter(apiHeaderFilter());
    registration.addUrlPatterns("/example/*");
    registration.setName("apiHeaderFilter");
    registration.setOrder(1);
    return registration;
} 

@Bean(name = "ApiHeaderFilter")
public Filter apiHeaderFilter() {
    return new ApiHeaderFilter();
}

跳过请求

如果您在@RequestMapping中使用headers属性

@RequestMapping(value = "/test", method = RequestMethod.POST,
    headers = {"content-type=application/json"})

如果没有其他处理程序接受请求，

将导致404。

Answer 3

有一个功能请求Spring积压，结帐JIRA。但是，我能够在Controller上使用PostgreSQL注释来实现您的尝试。

@Validated

此处@RestController @RequestMapping("/user") @Validated public class UserController { @GetMapping("/{loginId}") public User getUserBy(@PathVariable @LoginID final String loginId) { // return some user } }是自定义验证程序。而@LoginID来自@Validated，可以解决问题。

Answer 4

只需添加以下类。在“ doFilter”方法内进行任何验证，并设置适当的响应代码。

@Configuration
public class ApiHeaderFilter extends GenericFilterBean {

    @Override
    public void doFilter(ServletRequest servletRequest, ServletResponse servletResponse, FilterChain filterChain) throws IOException, ServletException {
        HttpServletRequest request = (HttpServletRequest)servletRequest;
        HttpServletResponse response = (HttpServletResponse)servletResponse;
        String token = request.getHeader("token");
        if (StringUtil.isNullOrEmpty(token)) {
            response.sendError(HttpServletResponse.SC_UNAUTHORIZED);
            return;
        }
        filterChain.doFilter(servletRequest,servletResponse);
    }
}

REST端点Spring Boot中参数的自定义验证逻辑

4 个答案: