Question

我正在尝试构建一个创建密码的gui，并且我已经生成了密码并使其显示在标签中。但是，当多次单击该按钮时，似乎旧密码不会消失，它只是覆盖在顶部。我也得到一个我似乎无法纠正的错误，虽然它似乎不会影响gui。

目前的代码是：

from tkinter import *
import random

myGui = Tk()
myGui.geometry('300x200+700+250')
myGui.title('Password Generator')

def passwordgen():
    password = ''

    for i in range(8):
        ##----runs the for loop 8 times
        if (i == 0) or (i == 4):
            password = password + chr(random.randint(97, 122))

        if (i == 1) or (i == 5):
            password = password + chr(random.randint(65, 90))

        if (i == 2) or (i == 6):
            password = password + chr(random.randint(48, 57))

        if (i == 3) or (i == 7):
            password = password + chr(random.randint(33, 47))

    passLabel = Label(myGui, text=password)
    passLabel.grid(row=0, column=1, sticky=E)

genPassBtn = Button(myGui, text="Generate Password", command=passwordgen)
genPassBtn.bind("<Button-1>", passwordgen)
genPassBtn.grid(row=0, column=0, sticky=W)

myGui.mainloop()

我收到的错误是：

return self.func(*args)
TypeError: passwordgen() takes 0 positional arguments but 1 was given

我希望实现的结果是创建一个生成密码的gui，为生成的密码生成哈希值，检查密码强度，将生成的哈希加载到文本文件，然后可以针对存储的哈希验证密码

此外，根据收到的建议，我已经修改了代码，并增加了额外的检查力度。代码现在看起来像这样：

from tkinter import *
import random

myGui = Tk()
myGui.geometry('300x200+700+250')
myGui.title('Password Generator')

def passwordgen():
    password = ''

    for i in range(8):
        ##----runs the for loop 8 times
        if (i == 0) or (i == 4):
            password = password + chr(random.randint(97, 122))

        if (i == 1) or (i == 5):
            password = password + chr(random.randint(65, 90))

        if (i == 2) or (i == 6):
            password = password + chr(random.randint(48, 57))

        if (i == 3) or (i == 7):
            password = password + chr(random.randint(33, 47))

    strPassword.set(password)


def checkPassword():

    strength = ['Blank', 'Very Weak', 'Weak', 'Medium', 'Strong', 'Very Strong']
    score = 1
    password = strPassword.get()

    if len(password) < 1:
        return strength[0]

    if len(password) < 4:
        return strength[1]

    if len(password) >= 8:
        score += 1

    if re.search('[0-9]', password):
        score += 1

    if re.search('[a-z]', password) and re.search('[A-Z]', password):
        score += 1

    if re.search('.', password):
        score += 1

    passwordStrength.set(strength[score])

genPassBtn = Button(myGui, text="Generate Password", command=passwordgen)
strPassword = StringVar()

lblPassword = Label(myGui, textvariable=strPassword)
lblPassword.grid(row=0, column=1, sticky=W)
genPassBtn.grid(row=0, column=0, sticky=W)

passwordStrength = StringVar()
checkStrBtn = Button(myGui, text="Check Strength", command=checkPassword)
checkStrBtn.grid(row=1, column=0)

checkStrLab = Label(myGui, textvariable=passwordStrength)
checkStrLab.grid(row=1, column=1)

myGui.mainloop()

Answer 1

试试这个例子。

from tkinter import *
import random

myGui = Tk()
myGui.geometry('300x200+700+250')
myGui.title('Password Generator')

def passwordgen():
    password = ''

    for i in range(8):
        ##----runs the for loop 8 times
        if (i == 0) or (i == 4):
            password = password + chr(random.randint(97, 122))

        if (i == 1) or (i == 5):
            password = password + chr(random.randint(65, 90))

        if (i == 2) or (i == 6):
            password = password + chr(random.randint(48, 57))

        if (i == 3) or (i == 7):
            password = password + chr(random.randint(33, 47))

    strPassword.set(password)

genPassBtn = Button(myGui, text="Generate Password", command=passwordgen)
strPassword = StringVar()
lblPassword = Label(myGui, textvariable=strPassword)
lblPassword.grid(row=0,column=1, sticky=W)
genPassBtn.grid(row=0, column=0, sticky=W)

myGui.mainloop()

这就是我所做的

我不是每次都创建一个新标签，而是使用名为strPassword的StringVar更改标签的文本。
您不需要将按钮绑定到单击以调用函数，使用Button（...，command = myFunction）已经这样做了。

Python Tkinter标签刷新

1 个答案: