重定向到外部URL servlet过滤器

Question

我无法在servlet过滤器中重定向用户。

@WebFilter(value = "/*", initParams = { @WebInitParam(name = "applicationClassName", value = "com.sample.Application"),
@WebInitParam(name="filterMappingUrlPattern", value="/*") })
public class CertFilter extends WicketFilter {

    @Override
    public void doFilter(final ServletRequest request, final ServletResponse response, final FilterChain chain) throws IOException, ServletException {
        HttpServletResponse httpServletResponse = (HttpServletResponse) servletResponse;
        HttpServletRequest httpServletRequest = (HttpServletRequest) servletRequest;
        if(USER_MATCHES_CONDITION){
            httpServletResponse.setHeader("Location", "https://google.com");
            httpServletResponse.sendRedirect("https://google.com");
        }
        filterChain.doFilter(httpServletRequest, httpServletResponse);
    }
}

google.com的请求已完成，但用户未被重定向到那里。截获的请求意味着在请求样式表时满足USER_MATCHES_CONDITION。因此，重定向请求标头为Accept:text/css,*/*;q=0.1。所以我得到一个警告资源解释为样式表，但转移MIME类型text / html。可能这就是它没有重定向的原因。

如何拦截随机请求并将其重定向到外部网址？

编辑：即使我这样做：

@Override
    public void doFilter(final ServletRequest request, final ServletResponse response, final FilterChain chain) throws IOException, ServletException {
        HttpServletResponse httpServletResponse = (HttpServletResponse) servletResponse;
        HttpServletRequest httpServletRequest = (HttpServletRequest) servletRequest;
        httpServletResponse.sendRedirect("https://google.com");
        return;
    }

它没有重定向用户...我猜wicket以某种方式覆盖它。