问题

我想将位图2 叠加到位图1 上，说位图2 应该高于位图1 。< / p>

位图2 应该获取位图1 的宽度和高度以覆盖所有内容。

位图1 将具有任何宽度和高度，但是，我希望位图2 应该获得位图1的宽度和高度无论如何。

我的代码问题是庄稼 位图1 ，然后将位图2 覆盖到它上面。我的意思是代码获得 Bitmap 2 宽度和高度！

我做了什么

public Bitmap overlay123(Bitmap bmp1, Bitmap bmp2) {
            Bitmap bmOverlay = Bitmap.createBitmap(bmp2.getWidth(), bmp2.getHeight(), bmp1.getConfig());
            float left =(bmp2.getWidth() - (bmp1.getWidth()*((float)bmp2.getHeight()/(float)bmp1.getHeight())))/(float)2.0;
            float bmp1newW = bmp1.getWidth()*((float)bmp2.getHeight()/(float)bmp1.getHeight());
            Bitmap bmp1new = getResizedBitmap(bmp1, bmp2.getHeight(), (int)bmp1newW);
            Canvas canvas = new Canvas(bmOverlay);
            canvas.drawBitmap(bmp1new, left ,0 , null);
            canvas.drawBitmap(bmp2, new Matrix(), null);
            return bmOverlay;
        }

        public Bitmap getResizedBitmap(Bitmap bm, int newHeight, int newWidth) {
            int width = bm.getWidth();
            int height = bm.getHeight();
            float scaleWidth = ((float) newWidth) / width;
            float scaleHeight = ((float) newHeight) / height;
            Matrix matrix = new Matrix();
            matrix.postScale(scaleWidth, scaleHeight);
            Bitmap resizedBitmap = Bitmap.createBitmap(bm, 0, 0, width, height, matrix, false);
            return resizedBitmap;
}

以上代码的问题在于裁剪或调整位图1 的宽度和高度！

尝试2

private Bitmap overlayer(Bitmap bmp1, Bitmap bmp2) {
    Bitmap bmOverlay = Bitmap.createBitmap(bmp1.getWidth(), bmp1.getHeight(), bmp1.getConfig());
    Canvas canvas = new Canvas(bmOverlay);
    canvas.drawBitmap(bmp1, new Matrix(), null);
    canvas.drawBitmap(bmp2, new Matrix(), null);
    return bmOverlay;
}

代码问题是它总是在左上角显示位图2 ，尺寸较小！

我只需要知道如何将位图2 放在位图1 上，使其宽度和高度与位图1 相同。< / p>

我是Bitmap代码的新手，所以我不知道它

先谢谢！

最终图片应如下所示：

Answer 1

MainActivity Output.

string str = @"a\b";

var result = str.Split('\\'); // work (case 1)

//var result = str.Split(new char['\\']); not work as what I want and will print a\b (case 2)

foreach (var r in result)
    Console.WriteLine(r);

<强> activity_main.xml中

public class MainActivity extends Activity {
    private ImageView Img;

    /**
     * Called when the activity is first created.
     */
    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);

        Button button = (Button) findViewById(R.id.button);
        Img = (ImageView) findViewById(R.id.imageView);
        button.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View v) {
                Bitmap bm = BitmapFactory.decodeResource(getResources(), R.drawable.top);
                Bitmap bmt = BitmapFactory.decodeResource(getResources(), R.drawable.back);
                Img.setImageBitmap(overlayer(bm, bmt));

            }
        });
    }
    private Bitmap overlayer(Bitmap bmp1, Bitmap bmp2) {
        Bitmap bmOverlay = Bitmap.createBitmap(bmp1.getWidth(), bmp1.getHeight(), bmp1.getConfig());
        Canvas canvas = new Canvas(bmOverlay);
        canvas.drawBitmap(bmp1, new Matrix(), null);
        canvas.drawBitmap(bmp2, new Matrix(), null);
        return bmOverlay;
    }
}

<强>输出：

Output result see here.

Answer 2

首先，我建议您使用 Try2 作为进一步工作的基础。但我会略微修改代码：

private Bitmap overlayer(Bitmap bmp1, Bitmap bmp2) {
    Bitmap bmOverlay = Bitmap.createBitmap(bmp1.getWidth(), bmp1.getWidth(), bmp1.getConfig());
    Canvas canvas = new Canvas(bmOverlay);
    canvas.drawBitmap(bmp1, null, new Rect(0,0,bmp1.getWidth(),bmp1.getHeight()), new Paint());
    canvas.drawBitmap(bmp2, null, new Rect(0,0,bmp1.getWidth(),bmp1.getHeight()), new Paint());
    return bmOverlay;
}

我使用了android developer reference中提到的构造函数来绘制位图。您定义了一个新的Recatangle，该服务器作为用于缩放/绘制位图到画布的形状。在您的情况下，我定义的矩形与您的bitmap1大小相同。如果将此重新控制框交给绘制画布的方法，画布会将位图缩放到该框大小并在画布上绘制。

在另一个具有相同宽度和高度的位图上绘制位图

问题

我做了什么

尝试2

2 个答案: