Question

我的数据看起来像这样：

User     PaymentType         Month
-----------------------------------
A       Early Payment          1
A       Early Payment          2
A       Early Payment          3
A       Outstanding            4
A       Outstanding            5
A       Outstanding            6
B       Early Payment          1
B       Early Payment          2
B       Early Payment          3
B       Outstanding            4
B       Outstanding            5
B       Outstanding            6

如何为每个用户创建仅返回“Outstanding”PaymentType的最小月份的计算，然后可以将其作为数据中的新列放入？我需要跟踪每个用户第一个“杰出”PaymentType的时间。

Answer 1

{ FIXED [User] : MIN(IIF([Payment Type] = 'Outstanding', [Month], NULL)) } = [Month]

如果用户是未付款的第一个月，那么这将为您提供一个真实的列，否则为false。数据如下所示：

+------+---------------+-------+---------------------------+
| User | PaymentType   | Month | First Outstanding Payment |
+------+---------------+-------+---------------------------+
| A    | Early Payment | 1     | F                         |
| A    | Early Payment | 2     | F                         |
| A    | Early Payment | 3     | F                         |
| A    | Outstanding   | 4     | T                         |
| A    | Outstanding   | 5     | F                         |
| A    | Outstanding   | 6     | F                         |
| B    | Early Payment | 1     | F                         |
| B    | Early Payment | 2     | F                         |
| B    | Early Payment | 3     | F                         |
| B    | Outstanding   | 4     | T                         |
| B    | Outstanding   | 5     | F                         |
| B    | Outstanding   | 6     | F                         |
+------+---------------+-------+---------------------------+

请注意，这是针对您提供给我们的确切数据。例如，如果您的月份是日期字段（而不仅仅是数字），或者您为数据添加了多年，或者每月有多笔付款，则必须调整此公式。但是，这为您提供了如何计算您正在寻找的内容的基本概念，并且应该不难更新计算以满足您的需求。

如果bool不是您想要的，您可以取出条件，让该字段保存第一笔未付款的月份数。

{ FIXED [User] : MIN(IIF([Payment Type] = 'Outstanding', [Month], NULL)) }

在这种情况下，您的数据将如下所示：

+------+---------------+-------+---------------------------+
| User | PaymentType   | Month | First Outstanding Payment |
+------+---------------+-------+---------------------------+
| A    | Early Payment | 1     | 4                         |
| A    | Early Payment | 2     | 4                         |
| A    | Early Payment | 3     | 4                         |
| A    | Outstanding   | 4     | 4                         |
| A    | Outstanding   | 5     | 4                         |
| A    | Outstanding   | 6     | 4                         |
| B    | Early Payment | 1     | 4                         |
| B    | Early Payment | 2     | 4                         |
| B    | Early Payment | 3     | 4                         |
| B    | Outstanding   | 4     | 4                         |
| B    | Outstanding   | 5     | 4                         |
| B    | Outstanding   | 6     | 4                         |
+------+---------------+-------+---------------------------+

在Tableau中按组查找最小值

1 个答案: