Question

所以这是交易。现在我有一个用户可以注册的viewcontroller，它正在工作（在Firebase控制台中检查）。下一步是我有另一个带有两个字段和一个登录按钮的视图。该登录按钮现在具有到第三个视图的segue，home。但即使在两个文本字段中没有输入任何内容，也可以单击它。该按钮仅在用户输入他在注册视图中创建的详细信息时才起作用，从而登录。

我该怎么做？已经有登录代码：

@IBAction func loginAction(sender: AnyObject)
{
    if self.emailField.text == "" || self.passwordField.text == ""
    {
        let alertController = UIAlertController(title: "Oops!", message: "Please enter an email and password.", preferredStyle: .Alert)

        let defaultAction = UIAlertAction(title: "OK", style: .Cancel, handler: nil)
        alertController.addAction(defaultAction)

        self.presentViewController(alertController, animated: true, completion: nil)
    }
    else
    {
        FIRAuth.auth()?.signInWithEmail(self.emailField.text!, password: self.passwordField.text!) { (user, error) in

            if error == nil
            {
                self.emailField.text = ""
                self.passwordField.text = ""
            }
            else
            {
                let alertController = UIAlertController(title: "Oops!", message: error?.localizedDescription, preferredStyle: .Alert)

                let defaultAction = UIAlertAction(title: "OK", style: .Cancel, handler: nil)
                alertController.addAction(defaultAction)

                self.presentViewController(alertController, animated: true, completion: nil)
            }

在第二个if语句中，您会看到它清除字段以显示登录的工作情况。

我需要的是，只有填写了Firebase数据库中的正确详细信息，用户才能登录。

Answer 1

不是检查是否有任何错误，而是检查数据是否是这样的用户对象。

FIRAuth.auth()?.signInWithEmail(self.emailField.text!, password: self.passwordField.text!) { (user, error) in

        if user != nil
        {

        let VC = storyboard?.instantiateViewControllerWithIdentifier("Identifier") as! AccountViewController //The file that controls the view 

        self.presentViewController(VC, animated: true, completion: nil)

        }
        else
        {
            let alertController = UIAlertController(title: "Oops!", message: error?.localizedDescription, preferredStyle: .Alert)

            let defaultAction = UIAlertAction(title: "OK", style: .Cancel, handler: nil)
            alertController.addAction(defaultAction)

            self.presentViewController(alertController, animated: true, completion: nil)
        }

Answer 2

我设法通过添加自我修复它。面前

storyboard?.instantiate.

因此创造：

self.storyboard?instantiate.

Firebase登录系统

2 个答案: