这是我第一次使用dbs,我在基础知识方面遇到了一些麻烦。试图在网上看,但无法找到简单问题的答案。当我尝试向我的数据库添加一些信息时,我得到了一大堆错误。
import pymongo
def get_db():
from pymongo import MongoClient
client = MongoClient("mongodb://xxxxxx:xxxxxx@ds029735.mlab.com:29735/xxxxxxx")
db = client.myDB
return db
def add_country(db):
db.countries.insert({"name": "Canada"})
def get_country(db):
return db.contries.find_one()
db = get_db()
add_country(db)
我收到此错误消息:
File "/Users/vincentfortin/Desktop/Python_code/mongo.py", line 21, in <module>
add_country(db)
File "/Users/vincentfortin/Desktop/Python_code/mongo.py", line 11, in add_country
db.countries.insert({"name": "Canada"})
File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/pymongo/collection.py", line 2212, in insert
check_keys, manipulate, write_concern)
File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/pymongo/collection.py", line 535, in _insert
check_keys, manipulate, write_concern, op_id, bypass_doc_val)
File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/pymongo/collection.py", line 516, in _insert_one
check_keys=check_keys)
File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/pymongo/pool.py", line 239, in command
read_concern)
File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/pymongo/network.py", line 102, in command
helpers._check_command_response(response_doc, None, allowable_errors)
File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/pymongo/helpers.py", line 205, in _check_command_response
raise OperationFailure(msg % errmsg, code, response)
pymongo.errors.OperationFailure: not authorized on myDB to execute command { insert: "countries", ordered: true, documents: [ { _id: ObjectId('579a6c6ed51bef1274162ff4'), name: "Canada" } ] }
答案 0 :(得分:2)
如果xxxxxxx
的{{1}}与ds029735.mlab.com:29735/xxxxxxx
中的myDB
相等,请检查两次。我的意思是如果你的连接字符串是db = client.myDB
,那么你的代码应该是mongodb://username:password@ds029735.mlab.com:29735/xyz
而不是db = client.xyz
(或其他名称)。
如果您的用户是只读http://i.imgur.com/It32S1d.png
这两个问题都会像你一样返回错误,所以我不知道你遇到了哪一个。