Question

I have 2 sockets connecting and sending a file. I want at some point send a signal to the second socket. I thought of sending a string "start" and when the receiver socket gets it, I execute something. Below is the code for receiver and sender. What am I doing wrong? The receiver never gets the "start" and I am sure its being sent. Thanks

Sender Side:

byte[] buff = new byte[1024 * 50];    
while (isRunning && (readBytes = data.read(buff, 0, buff.length)) != -1) {
    client.getOutputStream().write(buff, 0, readBytes);
    if(sendStart){
        client.getOutputStream().("start".getBytes("UTF-8"), 0, "start".getBytes("UTF-8").length);
        sendStart = false;
    }
}

Receiver Side:

DataInputStream in = null;
   try {
        in = new DataInputStream(socket.getInputStream());
     } catch (IOException e) {
   }

byte buffer[] = new byte[1024 * 50]; 
while ((len = in.read(buffer)) != -1) {
    String received = new String(buffer, "UTF-8");
    if(received!=null && received.equals("start")){
        Log.d(TAG,"received start");
        //do something
    }
    receivedFile.write(buffer, 0, len);
}

Answer 1

我认为错误可能在这里：

client.getOutputStream().("start".getBytes("UTF-8"), 0, "start".getBytes("UTF-8").length);

如果你看，write()方法不在这一行的任何地方。另外，我想问一下，您是否有一个特殊原因要自己处理字符串序列化？您可以使用PrintWriter和Scanner之类的字符串，也可以将ObjectOutputStream和ObjectInputStream用于任何类型的对象。

Send a string between sockets in between bytes

1 个答案: