我知道有很多与此相关的代码!但我仍然面临着问题 我搜索了许多教程和文档,当我最小化应用程序时,我能够运行服务!但是当应用程序关闭或终止时它没有响应
这是我的代码!这是我的服务类
public class MyService extends Service {
final public static String ONE_TIME = "onetime";
public static final String MyPREFERENCES = "MyPrefs";
SharedPreferences sharedpreferences;
@Override
public IBinder onBind(Intent arg0) {
return null;
}
@Override
public void onStart(Intent intent, int startId) {
// TODO Auto-generated method stub
super.onStart(intent, startId);
Toast.makeText(this, "ServiceClass.onStart()", Toast.LENGTH_LONG).show();
Log.d("Testing", "Service got started");
}
@Override
public void onCreate() {
super.onCreate();
}
@Override
public int onStartCommand(Intent intent, int flags, int startId) {
sharedpreferences = getSharedPreferences(MyPREFERENCES, Context.MODE_PRIVATE);
//I need to call this every say-10 second
final String URL = "http://nrna.org.np/nrna_app/app_user/set_location/" + sharedpreferences.getString("Save_user_app_id", null) + "/np";
// if (isNetworkAvailable() == true) {
RequestQueue queue = Volley.newRequestQueue(MyService.this);
StringRequest stringRequest = new StringRequest(Request.Method.GET, URL, null, null);
// Add the request to the RequestQueue.
queue.add(stringRequest);
// Let it continue running until it is stopped.
Toast.makeText(this, "Service Started", Toast.LENGTH_LONG).show();
return START_STICKY;
}
@Override
public void onDestroy() {
super.onDestroy();
Toast.makeText(this, "Service Destroyed", Toast.LENGTH_LONG).show();
}
}
我从我的主要活动中调用了这项服务
// Method to start the service
public void startService(Context context) {
Intent intent = new Intent(MainActivity.this, MyService.class);
PendingIntent pintent = PendingIntent.getService(MainActivity.this, 0, intent, 0);
AlarmManager alarm = (AlarmManager)getSystemService(Context.ALARM_SERVICE);
alarm.setRepeating(AlarmManager.RTC_WAKEUP, System.currentTimeMillis(), 10 * 1000, pintent);
//startService(new Intent(getBaseContext(), MyService.class));
}
我的清单文件
<service android:name=".MyService"/>
如果应用已关闭,我需要运行!!
更新我使用过BroadCastReceiver!但不能再工作了。
public class BaseNotificationManager extends BroadcastReceiver {
public static final String BaseAction = "Com.TST.BaseAction";
public static final String FireService = "Com.TST.FireNotificationAction";
private static final long timeFrame = 1000*10; // 5 mints
public BaseNotificationManager() {
}
@Override
public void onReceive(Context context, Intent intent) {
if (Intent.ACTION_BOOT_COMPLETED.equals(intent.getAction())) {
/// add base alarm manager
startBaseAlarmManager(context);
}else if (BaseAction.equals(intent.getAction())){
// StartYourService();
intent = new Intent(context,MyService.class);
PendingIntent pintent = PendingIntent.getService(context, 0, intent, 0);
AlarmManager alarm = (AlarmManager)context.getSystemService(Context.ALARM_SERVICE);
alarm.setRepeating(AlarmManager.RTC_WAKEUP, System.currentTimeMillis(), 10 * 1000, pintent);
}
} public static void startBaseAlarmManager (Context context){
AlarmManager alarmMgr;
PendingIntent alarmIntent;
alarmMgr = (AlarmManager)context.getSystemService(Context.ALARM_SERVICE);
Intent intent = new Intent(context, BaseNotificationManager.class);
intent.setAction(BaseAction);
alarmIntent = PendingIntent.getBroadcast(context, 0, intent, 0);
alarmMgr.setRepeating(AlarmManager.ELAPSED_REALTIME_WAKEUP,
5000, timeFrame, alarmIntent);
}}
答案 0 :(得分:1)
您要做的是在服务的后台线程上运行某种循环。您的代码没有表明您希望重复操作。您真正想要的是以下内容(使用C#语法):
new Thread(obj =>
{
while (true)
{
// Do actions that you want repeated (poll web site, etc.)
// Sleep for awhile
Thread.Sleep(10000);
}
}
另见以下主题: Android Service Stops When App Is Closed
顺便说一下,我可能会误解你的目标,但你是否也可以使用推送通知(例如GCM)在这里完成同样的事情? (我问的原因是,从电源管理的角度来看,使用GCM往往比反复轮询更好。)
如果您有点好奇,那么就可以很好地谈论节约电力并让您的应用成为“好公民”#34;在Android Developers Backstage播客的电池寿命方面。我想你应该能够在这里得到它:https://www.acast.com/androiddevelopersbackstage/episode-44-power-on
修改:如果您要上传结果,可以执行以下操作将其发布到您的网络服务(再次使用C#/ Web API语法,但您可以轻松实现将Java与Web API或Node.js一起使用):
public class Location
{
public double Latitude
{
get;
set;
}
public double Longitude
{
get;
set;
}
public Location(double latitude, double longitude)
{
this.Latitude = latitude;
this.Longitude = longitude;
}
}
// This call goes in your main thread
private async void PostLocation(Location location)
{
using (var client = new HttpClient())
{
client.BaseAddress = new Uri("[your base address]");
string json = JsonConvert.SerializeObject(location);
HttpResponseMessage message = await client.PostAsync("controller/method", new StringContent(json));
}
}
答案 1 :(得分:1)
尝试
public class MyService extends Service {
@Override
protected void onHandleIntent(Intent workIntent) {
// Gets data from the incoming Intent
String dataString = workIntent.getDataString();
...
// Do work here, based on the contents of dataString
...
}
}
您的应用程序似乎有GUI,您正在使用Service类。这里的主要缺点是
Service
在后台中运行,但它在应用程序主线程上运行。
IntentService
在单独的工作线程上运行。