Question

我写了一个密码生成器，我遇到了这个恼人的问题，它是在同一行重复一个数字或字母。用户为程序提供了他们希望如何生成密码的格式，例如C @@ d %%%＆＃34; 其中@只是字母，％只是数字，用户也输入数字和字母来生成密码，然后程序打印出类似cold123的东西，但是打印出cood111或clld111，我会发布下面是我的代码片段，但请不要蹩脚，我对python很新，自学成才，几个月前就进入了python体验。

class G()
    .
    .
    .

    # self.forms is the format the user input they can input things such as C@@d%%% 
    # where @ is only letters and where % is only numbers

    # self.Bank is a list where generated things go 

    AlphaB = [] #list Of All Of The Positions That have The @ sign in The self.forms 
    NumB = [] #list of All of the positions that have a % sign
    for char in self.forms: 
        if char == '@':
            EOL=(self.Position) # Positions End Of Line
            Loc = self.forms[EOL] # Letter
            AlphaB.append(EOL)  


        if char == '%':
            EOL=(self.Position)
            Loc = self.forms[EOL]
            NumB.append(EOL)
        self.Position+=1 # Move right a position

    for pos in AlphaB: 
        for letter in self.alphas: #letters in The User Inputs
            GenPass=(self.forms.replace(self.forms[pos],letter))
            #Not Fully Formatted yet, because Only The letter been formatted
            if GenPass.find('%'):
                for Pos in NumB:
                    for number in self.ints:
                        GenPass=(GenPass.replace(GenPass[Pos],number))
                        if GenPass not in self.Bank:
                            #Cood111
                            print (GenPass)
                            self.Bank.append(GenPass)

            else:
                if GenPass not in self.Bank:
                    print (GenPass)
                    self.Bank.append(GenPass)

Answer 1

GenPass.replace(GenPass[Pos],number)会将GenPass[Pos]中的每个字符替换为number的值。您需要确保一次替换一个字符。

Answer 2

创建所有字符的列表和包含所有nums的列表，然后使用list.pop（randint（0，len（list） - 1）选择一个，你总是会选择一个不同的字母/数字，但是您还将被限制为10位数字（0-9）和20位字母。

如何阻止我的程序生成相同的密钥？

2 个答案: