Question

  
[0] => Array
        (
            [id] => 9
            [order_address_id] => 9
            [created] => 2015-12-17 12:24:20
            [order_status] => dispatched
            [total_discount] => 
            [total_shipping_charge] => 60
            [s_state] => NY
            [b_state] => NY
            [order_id] => 9
            [p_name] => Product 1
            [qty] => 1
            [price] => 475
        )

    [1] => Array
        (
            [id] => 9
            [order_address_id] => 9
            [created] => 2015-12-17 12:24:20
            [order_status] => dispatched
            [total_discount] => 
            [total_shipping_charge] => 60
            [s_state] => MA
            [b_state] => MA
            [order_id] => 9
            [p_name] => Product 2
            [qty] => 1
            [price] => 349
        )

我想找到具有相同ID重复的数组，然后我必须从具有相同id的第二个和后续数组中删除total_shipping_charge。我怎么能在PHP中做到这一点？

Answer 1

我会使用array_walk。

首先，您要创建一个回调函数来检查是否已经遇到id，如果有，则取消设置total_shipping_charge，如

function shipping_charge_walk(&$entry, $key, &$found_ids)
{
  if (in_array($entry['id'], $found_ids)) {
    unset($entry['total_shipping_charge']);
  } else {
    $found_ids[] = $entry['id'];
  }
}

这会通过引用获取$found_ids，以便它可以将任何遇到的ID附加到它，并通过引用获取$entry，以便它可以取消设置它的成员。

然后，只需在数组上调用array walk。

$found_ids = array();
array_walk($arr, 'shipping_charge_walk', $found_ids);

在PHP数组中传播重复值

1 个答案: