Question

尝试将一些静态数据发送到websocket并收到相同的内容。数据是

var details=
    [
      {
        "_id": "5799fac61ee480492224071a",
        "index": 0,
        "age": 25,
        "name": "Jean Pierce",
        "gender": "female",
        "email": "jeanpierce@cincyr.com"
      },
      {
        "_id": "5799fac678aae9a71af63ef2",
        "index": 1,
        "age": 23,
        "name": "Laurie Lopez",
        "gender": "female",
        "email": "laurielopez@cincyr.com"
      },
      {
        "_id": "5799fac6c237d929693c08d7",
        "index": 2,
        "age": 21,
        "name": "Padilla Barrett",
        "gender": "male",
        "email": "padillabarrett@cincyr.com"
      }
    ];

当收到上述数据时，它采用字符串形式，因此我使用JSON.parse(data)将其解析为JSON并将其存储在本地变量中。现在，这里的问题是，对于解析，需要将其转换为[Object,Object]形式而不是控制台上的[object Object],[object Object]。怎么做到这一点？

更新：相同的代码如下，请检查。

使用以下代码将数据发送到websocket服务器

 if (client.readyState === client.OPEN) {               
                    client.send(JSON.stringify(details));                   
                }

在接收端，数据收到 -

client.onmessage = function(e) {
         console.log(" Fetched data :"+JSON.parse(e.data));
          this.setState({   val:   JSON.parse(e.data)
                    });
            }.bind(this);

第二个语句中的console.log()将结果显示为[object Object],[object Object]，但需要在反应[ Object Object]中解析相同内容。怎么做到这一点？

Answer 1

你走了：

console.log('[' + array.fill('Object').toString() + ']')

测试：

var array = [
  {
    "_id": "5799fac61ee480492224071a",
    "index": 0,
    "age": 25,
    "name": "Jean Pierce",
    "gender": "female",
    "email": "jeanpierce@cincyr.com"
  },
  {
    "_id": "5799fac678aae9a71af63ef2",
    "index": 1,
    "age": 23,
    "name": "Laurie Lopez",
    "gender": "female",
    "email": "laurielopez@cincyr.com"
  },
  {
    "_id": "5799fac6c237d929693c08d7",
    "index": 2,
    "age": 21,
    "name": "Padilla Barrett",
    "gender": "male",
    "email": "padillabarrett@cincyr.com"
  }
]

console.log('[' + array.fill('Object').toString() + ']')

虽然我老实说不知道你为什么要这个而不是另一个 - 两者都同样（不）有帮助。您确定不想要console.dir吗？

如何在javascript中将[object Object]，[object Object]转换为[Object，Object]？

1 个答案: