Question

使用MySQL 5.6我试图在过去12个月中为每个inspections选择总month，如果没有，则输出为0。我似乎在这里遗漏了一些东西，因为输出都是NULL。 date_inspected字段只是常规SQL date

根据我的理解，结构应该是[conditional statement, output variable, default value]，但即使是0也会被忽略而支持NULL。我想知道我在这里做错了什么。

表：

Column          Type        Null    
id              int(11)     No           
inspector_id    int(11)     Yes          
company_id      int(11)     Yes      
date_inspected  date        No           
start_time      datetime    No           
end_time        datetime    No

查询：

SELECT
  SUM(IF(MONTH = 'Jan', total, 0)) AS 'Januari',
  SUM(IF(MONTH = 'Feb', total, 0)) AS 'Februari',
  SUM(IF(MONTH = 'Mar', total, 0)) AS 'Maart',
  SUM(IF(MONTH = 'Apr', total, 0)) AS 'April',
  SUM(IF(MONTH = 'May', total, 0)) AS 'Mei',
  SUM(IF(MONTH = 'Jun', total, 0)) AS 'Juni',
  SUM(IF(MONTH = 'Jul', total, 0)) AS 'Juli',
  SUM(IF(MONTH = 'Aug', total, 0)) AS 'Augustus',
  SUM(IF(MONTH = 'Sep', total, 0)) AS 'September',
  SUM(IF(MONTH = 'Oct', total, 0)) AS 'Oktober',
  SUM(IF(MONTH = 'Nov', total, 0)) AS 'November',
  SUM(IF(MONTH = 'Dec', total, 0)) AS 'December',
  SUM(total) AS all_months
  FROM (
        SELECT MONTH(date_inspected) AS MONTH, COUNT(*) AS total
        FROM inspection
        WHERE date_inspected BETWEEN NOW() AND Date_add(NOW(), interval - 12 month)
        GROUP BY MONTH
  ) AS SubTable

输出

{ ["Januari"]=> NULL 
["Februari"]=> NULL 
["Maart"]=> NULL 
["April"]=> NULL 
["Mei"]=> NULL 
["Juni"]=> NULL 
["Juli"]=> NULL 
["Augustus"]=> NULL 
["September"]=> NULL 
["Oktober"]=> NULL 
["November"]=> NULL 
["December"]=> NULL 
["all_months"]=> NULL }

更新

Gordon Linoff

解决方案

SELECT
     SUM(CASE WHEN MONTH(date_inspected) = 1 THEN 1 ELSE 0 END) AS 'Januari',
     SUM(CASE WHEN MONTH(date_inspected) = 2 THEN 1 ELSE 0 END) AS 'Februari',
     SUM(CASE WHEN MONTH(date_inspected) = 3 THEN 1 ELSE 0 END) AS 'Maart',
     SUM(CASE WHEN MONTH(date_inspected) = 4 THEN 1 ELSE 0 END) AS 'April',
     SUM(CASE WHEN MONTH(date_inspected) = 5 THEN 1 ELSE 0 END) AS 'Mei',
     SUM(CASE WHEN MONTH(date_inspected) = 6 THEN 1 ELSE 0 END) AS 'Juni',
     SUM(CASE WHEN MONTH(date_inspected) = 7 THEN 1 ELSE 0 END) AS 'Juli',
     SUM(CASE WHEN MONTH(date_inspected) = 8 THEN 1 ELSE 0 END) AS 'Augustus',
     SUM(CASE WHEN MONTH(date_inspected) = 9 THEN 1 ELSE 0 END) AS 'September',
     SUM(CASE WHEN MONTH(date_inspected) = 10 THEN 1 ELSE 0 END) AS 'Oktober',
     SUM(CASE WHEN MONTH(date_inspected) = 11 THEN 1 ELSE 0 END) AS 'November',
     SUM(CASE WHEN MONTH(date_inspected) = 12 THEN 1 ELSE 0 END) AS 'December'
FROM inspection
WHERE date_inspected BETWEEN Date_add(NOW(), interval - 12 month) AND  NOW()

据我了解，我们已经给SUM()一个条件CASE声明，如果当前记录的date_inspected的MONTH等于MySQL常量对于该值，返回true并将其添加到总计中，否则不执行任何操作。

MySQL按月选择为所有月份返回NULL

2 个答案: