Question

提示如何在Sequelize中使用JOIN？我有以下代码：

        db.User.findAll({
        attributes: ['id'],
        where: {vipEnd: {lt: expiresVip}, vip: true},
        limit: 100,
        order: 'id'
    }).then(function(users) {

就4而言，它看起来像这样：

SELECT "vkId" AS "id" 
FROM "user" AS "user" 
WHERE "user"."vipEnd" < 1469699683 --expiresVip
AND "user"."vip" = true 
ORDER BY id 
LIMIT '100';

如何实现这样的结果？

SELECT "vkId" AS "id" 
FROM "user" AS "user" 

LEFT JOIN "notification" ON "notification"."userId" = "user"."vkId"

WHERE "user"."vipEnd" < 1469699683
AND "user"."vip" = true 

AND "notification"."type" = 4
AND "notification"."expiresVipDate" < 1469699683

ORDER BY id 
LIMIT '100';

谢谢！

Answer 1

您需要定义模型的关联。例如： db.User.hasMany(db.Notification, {foreignKey: 'UserId'}); 使用属性包括在sequelize中：

db.User.findAll({
include: [{
    model: db.Notification,
    required: true//true INNER JOIN, false LEFT OUTER JOIN - default LEFT OUTER JOIN
}]}).then(function(user) {}, function(err) {
res.json(err, 400);});

您应该在这里咨询更多 http://docs.sequelizejs.com/en/latest/docs/associations/

在Sequelize中使用JOIN

1 个答案: