如何通过连接获取表记录？

Question

假设我有数据库表X_tush，其中有列许可证，所以对于每个许可证说123我有n个与之关联的列，比如address_id，status，address_type等。 对于每个许可证我有n个网络说（101,102,108,113,114） 因此对于123许可证，存在101,102,114的3条记录和108,113的2条记录。 你能不能帮助复制101,102,114为113,108存在的记录，因为只有2条记录与之关联？

select * from xpna;

- 获取所需的所有网络

select distinct network from x_pns_address where network in    (101,102,113,114,108

）进入临终;

- 识别所有具有5个以下网络的许可证

SELECT license,address_type ,contact ,address_line1,address_line2,city  FROM xpna WHERE network IN (101,102,108,113,114) GROUP BY license,address_type ,contact ,address_line1,address_line2,city  HAVING COUNT(network) < 5 into temp msn;

select * from msn,aln into temp table1;

- 在Temp表中插入缺失值

INSERT INTO xpna
SELECT n.license, n.network, n.address_type , n.contact ,    n.address_line1, n.address_line2, n.city   FROM table1 as n 
LEFT  JOIN  x_pns_address  x
on x.network = n.network and x.license = n.license
group by x.address_type
where x.license is null;

select * from xpna;