如何在选择中找到所有区域(也是regeon类型)? 如果我们调用这个方法:
def chk_links(self,vspace):
url_regions = vspace.find_all("https?://[^\"'\s]+")
i=0
for region in url_regions:
cl = vspace.substr(region)
code = self.get_response(cl)
vspace.add_regions('url'+str(i), [region], "mark", "Packages/User/icons/"+str(code)+".png")
i = i+1
return i
在视图上下文中,例如:
chk_links(self.view)
一切正常,但这样:
chk_links(self.view.sel()[0])
我收到错误:AttributeError:'Region'对象没有属性'find_all'
您可以找到here
的完整插件代码答案 0 :(得分:3)
Selection
类(由View.sel()
返回)基本上只是表示当前选择的Region
个对象的列表。 Region
可以为空,因此列表始终包含至少一个长度为0的区域。
唯一的methods available on the Selection
class是修改和查询它的范围。类似methods are available on the Region
class。
您可以做的是找到您代码当前正在进行的所有有趣区域,然后在迭代它们以执行检查时,查看它们是否包含在选择中或不。
这是上面示例的精简版本,以说明这一点(为清楚起见,您的一些逻辑已被删除)。首先收集整个URL列表,然后在迭代列表时,只有在 NO 选择或 THERE IS时才会考虑每个区域 选择 AND 网址区域包含在选择范围内。
import sublime, sublime_plugin
class ExampleCommand(sublime_plugin.TextCommand):
# Check all links in view
def check_links(self, view):
# The view selection list always has at least one item; if its length is
# 0, then there is no selection; otherwise one or more regions are
# selected.
has_selection = len(view.sel()[0]) > 0
# Find all URL's in the view
url_regions = view.find_all ("https?://[^\"'\s]+")
i = 0
for region in url_regions:
# Skip any URL regions that aren't contained in the selection.
if has_selection and not view.sel ().contains (region):
continue
# Region is either in the selection or there is no selection; process
# Check and
view.add_regions ('url'+str(i), [region], "mark", "Packages/Default/Icon.png")
i = i + 1
def run(self, edit):
if self.view.is_read_only() or self.view.size () == 0:
return
self.check_links (self.view)