Question

首先是我的学生。我只是试图在这样的$ _POST php语句中进行循环

if ($_POST) { //Get value of Latitude, Longitude, Radius from site.php to calculate in Query above
    include('config/dbconnect.php'); //Database connection
    $lat = array();
    $lon = array();
    $rad = array();
    $stmt = array();
    $sql = array();

    $lat1 = $_POST['lat1']; //Get value of Latitude 1
    $lon1 = $_POST['lon1']; //Get value of Longitude 1
    $rad1 = $_POST['rad1']; //Get value of Radius 1
    $endrow = $_POST['endrow'];

    for ($i = 2; $i <= $endrow; $i++) {
        $lat[$i] = $_POST['lat'.$i]; //Get value of Latitude n
        $lon[$i] = $_POST['lon'.$i]; //Get value of Longitude n
        $rad[$i] = $_POST['rad'.$i]; //Get value of Radius n
    }

    //Haversine Formula and view only match Site CI and d2g_trx CI
    $sql = "SELECT site.*,d2g_trx.*, 
       ( 6371 * acos( cos( radians($lat1) ) 
                      * cos( radians( site.latitude ) ) 
                      * cos( radians( site.longitude ) - radians($lon1) ) 
                    +   sin( radians($lat1) ) 
                      * sin( radians( site.latitude ) ) ) ) AS distance 
       FROM site 
       INNER JOIN d2g_trx ON site.ci = d2g_trx.CI 
       HAVING distance <=$rad1 
       ORDER BY distance 
       LIMIT 0 , 50"; 

    $stmt = $dbh->query($sql)->fetchAll(); // Input 1

    for ($j = 2; $j <= $endrow; $j++) {
        //Haversine Formula and view only match Site CI and d2g_trx CI
        $sql[$j] = "SELECT site.*,d2g_trx.*, 
           ( 6371 * acos( cos( radians($lat[$j]) ) 
                          * cos( radians( site.latitude ) ) 
                          * cos( radians( site.longitude ) - radians($lon[$j]) ) 
                        +   sin( radians($lat[$j]) ) 
                          * sin( radians( site.latitude ) ) ) ) AS distance 
           FROM site 
           INNER JOIN d2g_trx ON site.ci = d2g_trx.CI 
           HAVING distance <=$rad[$j] 
           ORDER BY distance 
           LIMIT 0 , 50"; 
        $stmt[$j] = $dbh->query($sql[$j])->fetchAll(); //Input n
    }
}

我得到了这样的错误

致命错误：在非对象中调用成员函数fetchAll（）第28行的F：\ XAMPP \ htdocs \ kp \ getsite.php

无论如何，第28行就是这个

$stmt[$j]= $dbh->query($sql[$j])->fetchAll(); //Input n

对不起，我的英语非常糟糕:(

知道怎么解决这个先生吗？

之前谢谢

Answer 1

仅仅因为你可以这样做：

$dbh->query($sql[$j])->fetchAll();

并不代表你应该这样做。至少出于测试目的，您应该真正查看返回值（我假设您使用PDO）：

$result = $db->query($sql[$j]);
if($result === false) {
    print_r($db->errorInfo());
    exit;
}
$stmt[$j] = $result->fetch();

Answer 2

最后，它可能就像这样

if( $_POST ){ //Get value of Latitude, Longitude, Radius from site.php to calculate in Query above
include('config/dbconnect.php'); //Database connection
$tempsss = array("");
$lat = array("");
$lon = array("");
$rad = array("");  

$j=1;
foreach($_POST as $k => $v) {
    if(strpos($k, 'lat') === 0) {
        $lat[$j] =$v; //Get value of Latitude
        $j++;
    }
};
$z=1;
foreach($_POST as $k => $v) {
    if(strpos($k, 'lon') === 0) {
        $lon[$z] =$v; //Get value of Latitude
        $z++;
    }
};
$h=1;
foreach($_POST as $k => $v) {
    if(strpos($k, 'rad') === 0) {
        $rad[$h] =$v; //Get value of Latitude
        $h++;
    }
};

PHP - 在PHP查询中循环$ _POST

2 个答案: