Question

如何在sql server 2008中减去两个时间值。我在存储过程中使用时间变量。

请帮助

Answer 1

您可以使用DATEDIFF()：

SELECT DATEDIFF(Day, startDate, endDate)
  FROM table

SELECT DATEDIFF(Second, date, GETDATE())
  FROM table

Answer 2

DECLARE @END TIME = '16:00:00.0000000' ,    
     @START TIME = '01:00:00.0000000'
     SELECT convert(TIME,dateadd(ms,DateDiff(ss, @START, @END )*1000,0),114)

Answer 3

以下表达式适用于我

declare @starttime Time, @endtime Time
set @starttime='18:45'
set @endtime='22:45'
select DATEDIFF(HH,@starttime, @endtime)

输出：4

Answer 4

即使您使用的是偏移值或正常日期，此代码也会为您提供适当的答案。

   BEGIN TRY
DECLARE @OffSetVal1 VARCHAR(39) = '2019-12-02 09:15:29 +14:00'
      , @OffSetVal2 VARCHAR(39) = '2019-12-02 09:15:29 +12:30'
      , @minutes INT = 0
      , @OffSetDiff VARCHAR(19) = ''
      , @HourDiff INT = 0

SET @HourDiff = DATEDIFF(HOUR,@OffSetVal1,@OffSetVal2) -- To Check digits of hours.
SET @minutes = DATEDIFF(MINUTE,@OffSetVal1,@OffSetVal2) -- To Convert minutes to hours.
SET @OffSetDiff = @minutes / 60 + (@minutes % 60) / 100.0 -- To Check '+' Or '-' And To Get Value. 


SELECT CASE WHEN CAST(@OffSetDiff AS FLOAT) <= 0  
            THEN (CASE WHEN @HourDiff < 10
                      THEN FORMAT(CAST(@OffSetDiff AS FLOAT),'0#.00')
                 ELSE FORMAT(CAST(@OffSetDiff AS FLOAT),'0#.00') 
                 END)
        ELSE (CASE WHEN @HourDiff < 10
                      THEN '+'+FORMAT(CAST(@OffSetDiff AS FLOAT),'0#.00')
                 ELSE '+'+FORMAT(CAST(@OffSetDiff AS FLOAT),'0#.00') 
                 END) 
        END

END TRY
BEGIN CATCH
PRINT N'It seems you provided an invalid DateTimeOffSet Parameter. '
END CATCH

ANS：-+01.30（＃时差与分钟和分钟的偏差，如果您不希望'+'只需从代码中删除然后运行代码）

在ms sql server 2008中减去两个时间值

4 个答案: