我有一个应用程序,我希望在周六或周日显示一些数据。 实际上我有一个分段控制,如果我按下我的一个选项(这将是周末)我想检查它是星期六或星期日,但只是第一个周末。
这就是我在分段控制中第一个选择当前日期的选项
dateevent是我用来检查是否是currentDate的变量 currentDate被声明为currentDate
if dateevent.earlierDate(self.currentDate).isEqualToDate(self.currentDate){
if NSCalendar.currentCalendar().isDate(dateevent, equalToDate: self.currentDate, toUnitGranularity: .Day){
//Do something
}
}
答案 0 :(得分:4)
首先查找要添加到NSDateComponents
weekday
媒体资源的天数,然后您可以使用dateByAddingComponents(_:toDate:options:)
。
let today = NSDate()
let calendar = NSCalendar.currentCalendar()
let todayWeekday = calendar.component(.Weekday, fromDate: today)
let addWeekdays = 7 - todayWeekday // 7: Saturday number
var components = NSDateComponents()
components.weekday = addWeekdays
let nextSaturday = calendar.dateByAddingComponents(components, toDate: today, options: .MatchFirst)
答案 1 :(得分:3)
来自Apple docs:
如果日期确实属于周末,您可以使用
rangeOfWeekendStartDate:interval:containingDate:
方法确定 那个周末期间的开始日期。否则,你可以使用nextWeekendStartDate:interval:options:afterDate:
方法确定 下周末或上周末的开始日期。
答案 2 :(得分:0)
获取星期几的延期
func dayOfTheWeek() -> String? {
let dateFormatter = NSDateFormatter()
dateFormatter.locale = NSLocale(localeIdentifier: "en_US")
dateFormatter.dateFormat = "EEEE"
return dateFormatter.stringFromDate(self)
}
然后您可以计算周末需要多少天并将其添加到NSDate
NSDate().dateByAddingTimeInterval(60 * 60 * 24 * daysFromTodayToWeekend)
答案 3 :(得分:0)
Swift 4解决方案
我已经根据自己的要求弄清楚了,在那里我找到了后续的日期。
1. Today
2. Tomorrow
3. This Week
4. This Weekend
5. Next Week
6. Next Weekend
因此,我创建了Date Extension
来获取当前周和下周的日期。
代码
extension Date {
func getWeekDates() -> (thisWeek:[Date],nextWeek:[Date]) {
var tuple: (thisWeek:[Date],nextWeek:[Date])
var arrThisWeek: [Date] = []
for i in 0..<7 {
arrThisWeek.append(Calendar.current.date(byAdding: .day, value: i, to: startOfWeek)!)
}
var arrNextWeek: [Date] = []
for i in 1...7 {
arrNextWeek.append(Calendar.current.date(byAdding: .day, value: i, to: arrThisWeek.last!)!)
}
tuple = (thisWeek: arrThisWeek,nextWeek: arrNextWeek)
return tuple
}
var tomorrow: Date {
return Calendar.current.date(byAdding: .day, value: 1, to: noon)!
}
var noon: Date {
return Calendar.current.date(bySettingHour: 12, minute: 0, second: 0, of: self)!
}
var startOfWeek: Date {
let gregorian = Calendar(identifier: .gregorian)
let sunday = gregorian.date(from: gregorian.dateComponents([.yearForWeekOfYear, .weekOfYear], from: self))
return gregorian.date(byAdding: .day, value: 1, to: sunday!)!
}
func toDate(format: String) -> String {
let formatter = DateFormatter()
formatter.dateFormat = format
return formatter.string(from: self)
}
}
用法:
let arrWeekDates = Date().getWeekDates() // Get dates of Current and Next week.
let dateFormat = "MMM dd" // Date format
let thisMon = arrWeekDates.thisWeek.first!.toDate(format: dateFormat)
let thisSat = arrWeekDates.thisWeek[arrWeekDates.thisWeek.count - 2].toDate(format: dateFormat)
let thisSun = arrWeekDates.thisWeek[arrWeekDates.thisWeek.count - 1].toDate(format: dateFormat)
let nextMon = arrWeekDates.nextWeek.first!.toDate(format: dateFormat)
let nextSat = arrWeekDates.nextWeek[arrWeekDates.nextWeek.count - 2].toDate(format: dateFormat)
let nextSun = arrWeekDates.nextWeek[arrWeekDates.nextWeek.count - 1].toDate(format: dateFormat)
print("Today: \(Date().toDate(format: dateFormat))") // Sep 26
print("Tomorrow: \(Date().tomorrow.toDate(format: dateFormat))") // Sep 27
print("This Week: \(thisMon) - \(thisSun)") // Sep 24 - Sep 30
print("This Weekend: \(thisSat) - \(thisSun)") // Sep 29 - Sep 30
print("Next Week: \(nextMon) - \(nextSun)") // Oct 01 - Oct 07
print("Next Weekend: \(nextSat) - \(nextSun)") // Oct 06 - Oct 07
您可以根据需要修改Extension
。
谢谢!
答案 4 :(得分:0)
我使用这个实现来获取下一个特定时间的星期六:
代码 (Swift 5):
func nextSaturday(atHour hour: Int, min: Int) -> Date {
let today = Date()
let daysToAdd = 7 - (Calendar.current.dateComponents([.weekday], from: today).weekday ?? 0 )
let nextSaturday = Calendar.current.date(byAdding: .day, value: daysToAdd, to: today)!
return Calendar.current.date(bySettingHour: hour, minute: min, second: 0, of: nextSaturday)!
}
使用方法:
nextSaturday(atHour: 10, min: 0)