获取python列表

Question

如何从列表中获取字符串&quot和autoRefresh之间的内容/commander/link/jobDetails/jobs/a2537f238-8622-11ee-a1a0-f0921c14c828?，如下所示，我只需要第一个匹配项（可能有多个匹配项）。< / p>

['something', 'something', ' something top.window.location.href = "/commander/link/jobDetails/jobs/a2537f238-8622-11ee-a1a0-f0921c14c828?autoRefresh=0&s=Jobs";">','something']

尝试

link = re.search('"(.*?)autoRefresh', big_list)
print link.group(1)

得到TypeError: expected string or buffer

Answer 1

您需要遍历列表，检查每个字符串：

big_list = ['something', 'something', ' something top.window.location.href = "/commander/link/jobDetails/jobs/a2537f238-8622-11ee-a1a0-f0921c14c828?autoRefresh=0&s=Jobs";">','something']

def get_all_subs(lst, pat, grp=0):
    patt = re.compile(pat)
    for s in lst:
        m = patt.search(s, grp)
        if m:
            yield m.group(grp)

print(list(get_all_subs(big_list, '"(.*?)autoRefresh', 1)))

或者在列表中拨打str.join并使用 findall ：

print(re.findall('"(.*?)autoRefresh', "".join(big_list)))

Answer 2

您可以使用以下内容：

re.search(r'(?<=&quot).*?(?=autoRefresh)', ''.join(YourList))