Question

我需要在JSON中返回一个字符串来组合json对象和json数组这是我需要的例子

 {

  "scode" : "62573000", "sname" : "Burn of right",
  "icd10" = [
    {"icode" : "T25.229?", "iname" : "Right foot"}
    {"icode" : "T25.22941?", "iname" : "left foot"}
  ],
  "refinement" = [
    {"rname" : "Refinement1"},
    {"rname" : "Refinement2"}
  ]
}

但我变得像这样

{
    "icdcode": "T25.229?",
    "snomedcode": "62537000",
    "snomedname": "Second degree burn of foot (disorder)",
    "icdname": "Burn of second degree of unspecified foot, episode of care unspecified"
}

这是代码

oJsonAry = new JSONArray();

        while (resultSet.next())
        {           
            JSONObject oJsonOther = new JSONObject();
            JSONObject oJsonRefine = new JSONObject();
            hMapotherwise = new HashMap<String, String>();

            maprule = (resultSet.getString("mapRule"));
            if (maprule.matches("OTHERWISE TRUE")|| maprule.matches("TRUE"))
            {
                strSnomedCode=resultSet.getString("referencedComponentId");
                hMapotherwise.put("snomedcode", strSnomedCode);

                strSnomedDesc=resultSet.getString("sctName");
                hMapotherwise.put("snomedname", strSnomedDesc);

                strIcdCode=resultSet.getString("mapTarget");
                hMapotherwise.put("icdcode", strIcdCode);

                strIcdName=resultSet.getString("icdName");
                hMapotherwise.put("icdname", strIcdName);

                oJsonOther.putAll(hMapotherwise);
                oJsonAry.add(oJsonOther);
            }
                refid = resultSet.getInt("refid");
                pipe = resultSet.getString("mapRule").split("\\|");

                if (pipe.length > 1)
                {
                    bSubmit = true;
                    oJsonRefine.put("maprule", pipe);

                    oJsonAry.add(oJsonRefine);
                }


                if(oJsonAry != null) 
                {
                    strJSON = oJsonAry.toJSONString();
                }
        }
        }

我需要在我的java代码中更改的内容是什么，我是新手，因此我会陷入困境。任何人都说如何克服这一点。最后我必须在strJSON中返回

Answer 1

您的代码没有意义。请在下次尝试更清楚。首先你的Json语法不正确。正确的应该是：

{
    "scode": "62573000",
    "sname": "Burn of right",
    "icd10": [{
        "icode": "T25.229?",
        "iname": "Right foot"
    }, {
        "icode": "T25.22941?",
        "iname": "left foot"
    }],
    "refinement": [{
        "rname": "Refinement1"
    }, {
        "rname": "Refinement2"
    }]
}

其次，您需要一种类型的返回，但在返回示例中使用的是不同的变量名称。（我们必须猜测。）

在你的问题中存在所有这些问题，我试图解决你的问题，所以让我们看看。你需要在你的时间内声明你的阵列。

        // Declare your arrays and main json outside of the while
    JSONArray arrayJsonIcd10 = new JSONArray();
    JSONArray arrayJsonRefinement = new JSONArray();
    JSONObject mainJsonObject = new JSONObject();

    while (resultSet.next())
    {           

        maprule = (resultSet.getString("mapRule"));
        if (maprule.matches("OTHERWISE TRUE")|| maprule.matches("TRUE"))
        {

            // create two objects inside the while to save your
            //objects that you need in the array
            JSONObject jsonObjectToScode = new JSONObject();
            JSONObject jsonObjectToRefinment = new JSONObject();

            strSnomedCode = resultSet.getString("referencedComponentId");
            mainJsonObject.put("snomedcode", strSnomedCode);

            strSnomedDesc = resultSet.getString("sctName");
            mainJsonObject.put("snomedname", strSnomedDesc);

            strIcdCode = resultSet.getString("mapTarget");
            jsonObjectToScode.put("icdcode", strIcdCode);

            strIcdName = resultSet.getString("icdName");
            jsonObjectToScode.put("icdName", strIcdName);

            arrayJsonIcd10.put(jsonObjectToScode);
        }
        refid = resultSet.getInt("refid");
        pipe = resultSet.getString("mapRule").split("\\|");

        if (pipe.length > 1)
        {
            bSubmit = true;
            jsonObjectToRefinment.put("rname", pipe);
            arrayJsonRefinement.put(jsonObjectToRefinment);

        }



    }
    mainJsonObject.put("icd10", arrayJsonIcd10 );
    mainJsonObject.put("refinement", arrayJsonRefinement);
    strJSON = mainJsonObject.toString();    

}

那就是它，但我仍然感到困惑，你是怎么想获得的（＆＃34; scode＆＃34;：＆＃34; 62573000＆＃34;，＆＃34; sname＆＃34;：＆＃34 ;正确的烧伤＆＃34;）如果值在while内。我想你需要另一个数组来保存这个值。

如何使用java获取JSON对象和JSON数组中的值

1 个答案: