将因子转换为整数,同时保持因子级排序

时间:2016-07-27 19:12:34

标签: r dataframe r-factor

我有一个R数据帧,其中一列是其级别具有隐式排序的因子。 如何按以下方式将因子级别转换为特定整数

  • "非常不同意" - > 1
  • "有点不同意" - > 2
  • "中性" - > 3
  • "有点同意" - > 4
  • "非常同意" - > 5

例如,这是我的数据框:

agree <- c("Strongly agree", "Somewhat disagree", "Somewhat agree",
           "Neutral", "Strongly agree", "Strongly disagree", "Neutral")
age <- c(41, 35, 29, 42, 31, 22, 58)

df <- data.frame(age, agree)
df
#   age             agree
# 1  41    Strongly agree
# 2  35 Somewhat disagree
# 3  29    Somewhat agree
# 4  42           Neutral
# 5  31    Strongly agree
# 6  22 Strongly disagree
# 7  58           Neutral

str(df)
# 'data.frame': 7 obs. of  2 variables:
#  $ age  : num  41 35 29 42 31 22 58
#  $ agree: Factor w/ 5 levels "Neutral","Somewhat agree",..: 4 3 2 1 4 5 1

现在,我想使用上面显示的映射将agree列转换为整数列。

我已经搜索了关于将因子转换为整数的其他问题,但它们与维持因子排序无关。

&#34; How to convert a factor to an integer\numeric without a loss of information?&#34;

&#34; Convert factor to integer&#34;

&#34; Convert factor to integer in a data frame&#34;

3 个答案:

答案 0 :(得分:6)

您需要首先定义因子的顺序:

ordering <- c("Strongly disagree", "Somewhat disagree", "Neutral", "Somewhat agree", "Strongly agree")

然后,当您第一次创建因子时,您应该使用该定义:

agreeFactor <- factor(agree, levels = ordering)

然后,您应该能够获得有序因素:

as.numeric(agreeFactor)

您也可以在使用as.numeric()时应用订单,但如果您决定稍后检索数字向量并忘记应用“levels =”参数,则会导致不一致。

e:如果要将数字直接导入数据框,只需使用:

df$agree <- as.numeric(factor(df$agree, levels = ordering))

答案 1 :(得分:1)

dplyr库对此类操作有一个有用的revalue函数:

library(plyr)
df$agree<-as.numeric( revalue(df$agree, c("Strongly disagree" = 1,
                     "Somewhat disagree" = 2,
                     "Neutral" = 3,
                     "Somewhat agree" = 4,
                     "Strongly agree" = 5)) )

排序因子的整体@tluh方法是一种更好的方法,因为它维护原始输入并将因子设置为正确的顺序。

答案 2 :(得分:0)

如果您的因子已经按级别排序,则可以使用以下函数将该因子转换为数字顺序。

Convert_Numeric = function(X) {
        L = levels(X)
        Y = as.numeric(factor(X, labels = seq(1:length(L))))
        return(Y)
}

这对于函数或dplyr尤其有用:

df %>%
       mutate(Numeric_version = Convert_Numeric(agree))
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