Question

我的JSON：

{
    "adresses": [
        {
            "region": "Auvergne-Rhône-Alpes",
            "pertinence": 0.41,
            "cp": "73200",
            "coordonnee": [
                45.6681753,
                6.3863336
            ],
            "rue": "Rue Pasteur",
            "osm_id": "8063355",
            "pays": "France",
            "ville": "Albertville",
            "quartier": "Le Parstet",
            "nom": "",
            "secteur": "Albertville",
            "numero": ""
        },
        {
            "region": "Auvergne-Rhône-Alpes",
            "pertinence": 0.41,
            "cp": "73200",
            "coordonnee": [
                45.6635769,
                6.3830012
            ],
            "rue": "Rue Pasteur",
            "osm_id": "69253010",
            "pays": "France",
            "ville": "Albertville",
            "quartier": "",
            "nom": "",
            "secteur": "Albertville",
            "numero": ""
        },
        {
            "region": "Auvergne-Rhône-Alpes",
            "pertinence": 0.41,
            "cp": "73400",
            "coordonnee": [
                45.7469095,
                6.4237485
            ],
            "rue": "Rue Pasteur",
            "osm_id": "170250718",
            "pays": "France",
            "ville": "Ugine",
            "quartier": "",
            "nom": "",
            "secteur": "Albertville",
            "numero": ""
        }
    ]
}

当“osm_id”等于变量时，我需要删除其中一个地址。

我已经开始将JSON放在ArrayList字符串中以删除我想要的行然后重做JSON。但元素“coordonnee”是一个数组，我不知道我该怎么做。

这是我的试用版：

    JSONObject req = reponse.convertToJsonObject();
    JSONArray adresses = req.getJSONArray( "adresses" );
    ArrayList<String> tab = new ArrayList<String>();
    for ( int i = 0; i < adresses.length(); i++ ) {
    JSONObject adr = adresses.getJSONObject( i );
    String line = adr.getString( "region" ) + " " + adr.getDouble( "pertinence" ) + " "
    + adr.getString( "cp" ) + " " + adr.getString( "coordonnee" )
    + " " + adr.getString( "rue" ) + " " + adr.getString( "osm_id" ) + " "
    + adr.getString( "pays" ) + " " + adr.getString( "ville" )
     + " " + adr.getString( "quartier" ) + " " + adr.getString( "nom" ) + " "
    + adr.getString( "secteur" ) + " " + adr.getString( "numero" );
    tab.add( line );
}

你能帮助我吗？

Answer 1

我认为这应该做你想要的。它将过滤掉任何与您提供的变量匹配的“osm_id”的地址。

JSONObject req = reponse.convertToJsonObject();
JSONArray filteredAddresses = new JSONArray();
String filterId = "..."; // put whatever your ID is here

JSONArray unfilteredAddresses = req.getJSONArray("adresses");
for (int i = 0; i < unfilteredAddresses.length(); i++){
    JSONObject addressJson = unfilteredAddresses.getJSONObject(i);
    if (!addressJson.has("osm_id") || !addressJson.getString("osm_id").equals(filterId)){
        filteredAddresses.put(addressJson);
    }
}
req.put("adresses", filteredAddresses);

如何在JAVA中删除JSON中的一行

1 个答案: