单击单元格时,对象将添加到数组中。此数组需要传递到另一个活动。出于测试目的,我已经传递了只有一个对象DoctorObject的数组。然后在下一个活动中,我使用.getName()将名称作为字符串,并在toast中显示。然而吐司是空的。
以下是代码的一些片段
对象:
public class DoctorObject implements Parcelable {
private List<Object> mChildrenList;
public DoctorObject(String name) {
Docname = name;
}
public DoctorObject (Parcel in){
this.DocPic = in.readInt();
this.Docname= in.readString();
this.Docspecialty = in.readString();
this.DocLocation = in.readString();
}
String Docname = "";
public String getDocname() {
return Docname;
}
public void setDocname(String docname) {
Docname = docname;
}
public int getDocPic() {
return DocPic;
}
public void setDocPic(int docPic) {
DocPic = docPic;
}
public String getDocspecialty() {
return Docspecialty;
}
public void setDocspecialty(String docspecialty) {
Docspecialty = docspecialty;
}
public String getDocLocation() {
return DocLocation;
}
public void setDocLocation(String docLocation) {
DocLocation = docLocation;
}
int DocPic;
String Docspecialty = "";
String DocLocation = "";
@Override
public int describeContents() {
return 0;
}
@Override
public void writeToParcel(Parcel dest, int flags) {
}
public static final Parcelable.Creator CREATOR = new Parcelable.Creator() {
public DoctorObject createFromParcel(Parcel in) {
return new DoctorObject(in);
}
public DoctorObject[] newArray(int size) {
return new DoctorObject[size];
}
};
的活动:
ArrayList<DoctorObject> selectedItems = new ArrayList<>();
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_create_my_team);
context = this;
/* Regular Expand listview
*/
// get the listview
expListView = (ExpandableListView) findViewById(R.id.newTeamListView);
// preparing list data
prepareListData();
listAdapter = new ExpandableListAdapter(this, listDataDoc, listDataChildStaff);
// setting list adapter
expListView.setAdapter(listAdapter);
// expListView.setChoiceMode(ListView.CHOICE_MODE_MULTIPLE_MODAL);
// Listview on child click listener
expListView.setOnChildClickListener(new ExpandableListView.OnChildClickListener() {
@Override
public boolean onChildClick(ExpandableListView parent, View v,
int groupPosition, int childPosition, long id) {
// TODO Auto-generated method stub
DoctorObject currentDoc = listDataDoc.get(groupPosition);
StaffObject currentStaff = listDataChildStaff.get(listDataDoc.get(groupPosition)).get(childPosition);
selectedItems.add(currentDoc);
String toastname = currentDoc.getDocname();
String toastStaff = currentStaff.getStaffname();
Toast.makeText(getApplicationContext(),
toastStaff,
Toast.LENGTH_SHORT).show();
return true;
}
});
/* End of regular expand listview
*/
nextButton = (Button) findViewById(R.id.nextbuttonTeam);
nextButton.setOnClickListener(new View.OnClickListener() {
public void onClick(View v) {
Intent myIntent = new Intent(CreateMyTeamActivity.this, CreateReferralTeamActivity.class);
myIntent.putParcelableArrayListExtra("NAME", selectedItems);
//myIntent.putExtra("Selections",selectedItems);
CreateMyTeamActivity.this.startActivity(myIntent);
}
});
}
下一个活动:
public class CreateReferralTeamActivity extends AppCompatActivity {
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_create_referral_team);
Intent b = getIntent();
ArrayList<DoctorObject> list = (ArrayList<DoctorObject>) b.getSerializableExtra("NAME");
String lists ="";
for (int i=0; i < list.size(); i++){
lists = list.get(i).getDocname();
}
//TextView text = (TextView) findViewById(R.id.sampleText);
//text.setText(lists);
Toast.makeText(getApplicationContext(),
lists,
Toast.LENGTH_SHORT).show();
}
}
当我运行它时,似乎数组是空的。
这是一个动画gif:
答案 0 :(得分:3)
如果T对象不是Parcelable对象,则可以使用Gson Library将ArrayList传递给另一个Activity。通用类型在哪里。在您的情况下,它是ArrayList
步骤1:首先使用Gradle脚本导入Gson库
在Gradle依赖项中添加此行
dependencies {
compile 'com.google.code.gson:gson:2.7'
}
步骤2:将ArrayList转换为JSON String并将JSON字符串从Activity 1传递给Activity 2
ArrayList<DoctorObject> doctors = new ArrayList<Location>();
doctors.add(new DoctorObject(params));
doctors.add(new DoctorObject(params));
Gson gson = new Gson();
String jsonString = gson.toJson(doctors);
Intent intent = new Intent(MainActivity.this,MapsActivity.class);
intent.putExtra("KEY",jsonString);
startActivity(intent);
步骤3:从Bundle获取JSON字符串并将其转换回ArrayList
import java.lang.reflect.Type;
Bundle bundle = getIntent().getExtras();
String jsonString = bundle.getString("KEY");
Gson gson = new Gson();
Type listOfdoctorType = new TypeToken<List<DoctorObject>>() {}.getType();
ArrayList<DoctorObject> doctors = gson.fromJson(jsonString,listOfdoctorType );
答案 1 :(得分:1)
使用getParcelableArrayListExtra
代替getSerializableExtra
,因为使用putParcelableArrayListExtra
从上一个活动发送ArrayList对象:
ArrayList<DoctorObject> list = b.getParcelableArrayListExtra("NAME");
答案 2 :(得分:1)
您无法DoctorObject#writeToParcel()
为空,即实际复制对象数据的内容。
@Override
public void writeToParcel(Parcel dest, int flags) {
// the order you write to the Parcel has to be the same order you read from the Parcel
dest.writeInt(DocPic);
dest.writeString(Docname);
dest.writeString(Docspecialty);
dest.writeString(DocLocation);
}
要在其他活动中回读您的数据,请使用getParcelableArrayListExtra
ArrayList<DoctorObject> list = b.getParcelableArrayListExtra("NAME");