Question

我有以下owl文件，想要将相关数据检索到给定的类。

<owl:Class rdf:about="http://purl.obolibrary.org/obo/DOID_0001">
            <rdfs:subClassOf rdf:resource="http://purl.obolibrary.org/obo/DOID_11"/>   
            <obo:IAO_11 rdf:datatype="http://www.w3.org/2001/XMLSchema#string">A def def def def.</obo:IAO_0000115> 
            <oboInOwl:hasDbXref rdf:datatype="http://www.w3.org/2001/XMLSchema#string">AA:006394</oboInOwl:hasDbXref>
            <oboInOwl:hasExactSynonym rdf:datatype="http://www.w3.org/2001/XMLSchema#string">abcde</oboInOwl:hasExactSynonym> 
            <rdfs:label rdf:datatype="http://www.w3.org/2001/XMLSchema#string">ABCDEFG</rdfs:label>
        </owl:Class>

例如，我想使用以下代码检索应该是DOID_11的subClassOf而不成功：

//create the reasoning model using the base
 OntModel inf = ModelFactory.createOntologyModel();

 // use the FileManager to find the input file
 InputStream in = FileManager.get().open(inputFileName);
 if ( in == null) {
     throw new IllegalArgumentException("File: " + inputFileName + " not found");
 }

 inf.read( in , "");

 ExtendedIterator <? > classes = inf.listClasses();
 while (classes.hasNext()) {
     OntClass essaClasse = (OntClass) classes.next();

     System.out.println("Classe: " + essaClasse.getLocalName());
     for (Iterator <? > i = essaClasse.listSubClasses(); i.hasNext();) {

         OntClass c = (OntClass) i.next();
         System.out.print("   " + c.getLocalName() + "\n");
     } // end for 
 }

我只是＆＃34; DOID_0001＆＃34;而不是＆＃34; DOID_0001＆＃34;和＆＃34; DOID_11＆＃34;。我还需要获取所有其他信息，例如＆＃34;＆＃34;和＆＃34;

Answer 1

不，你错了。你的本体论中的陈述是

DOID_0001 rdfs:subClassOf DOID_11

这意味着，DOID_11是DOID_0001的超类，反之亦然。如果你要求DOID_0001的所有子类，它确实只是将类本身作为微不足道的推理。

更新

可以通过

检索每个班级的语句

    StmtIterator stmtIterator = inf.listStatements(essaClasse, null, (RDFNode) null);
    while(stmtIterator.hasNext()) {
        Statement st = stmtIterator.next();
        Property p = st.getPredicate();
        RDFNode o = st.getObject();
        System.out.println(p + ":" + o);
    }

使用Jena检索owl文件数据

1 个答案:

更新