Question

假设在Oracle 10g中，我有一个这样的表：

id    | start_date | end_date   | value   | parent_id
----------------------------------------------------
1     | 01-01-2001 | 01-01-2002 | aaaaaa  | 3
2     | 01-01-2003 | 01-01-2004 | bbbbbb  | 3
3     | 01-01-2000 | 01-01-2005 | cccccc  | 4
4     | 01-01-1999 | 01-01-2006 | dddddd  |null

我希望看到父母填补的空白没有重叠。更具体地说，结果应该是这样的：

start_date | end_date   | value  | depth 
-----------------------------------------
01-01-1999 | 01-01-2000 | dddddd | 2
01-01-2000 | 01-01-2001 | cccccc | 1
01-01-2001 | 01-01-2002 | aaaaaa | 0
01-01-2002 | 01-01-2003 | cccccc | 1
01-01-2003 | 01-01-2004 | bbbbbb | 0
01-01-2004 | 01-01-2005 | cccccc | 1
01-01-2005 | 01-01-2006 | dddddd | 2

深度是达到该值的父级数，但可以超过2，因此最好使用递归。

您可以假设具有相同父级的句点没有重叠。所有这些都不使用存储过程，但随意带来CTE，窗口函数等。

Answer 1

是的，这是可能的。不知道它会有多好。

查询分为3个主要CTE：

用于生成输出目的所需日期范围的CTE
用于计算树中最大深度的CTE
一个CTE，用于将所有数据连接在一起，并使用row_number()窗口函数按深度标记更“理想”的行。

查询：

with date_ranges_cte as (
  select add_months(date '1999-01-01', (rownum-1) * 12) as start_date,
         add_months(date '1999-01-01', rownum * 12) as end_date
    from dual
  connect by rownum <= 7
), max_level_cte as (
  select max(level) as max_level
    from tbl
   start with parent_id is null
 connect by prior id = parent_id
), main_cte as (
  select d.start_date, 
         d.end_date,
         t.value,
         t.lvl,
         row_number() over (partition by d.start_date, d.end_date order by t.lvl desc, t.id) as rn
    from date_ranges_cte d
    join (select t.*, level as lvl
            from tbl t
           start with parent_id is null
         connect by prior id = parent_id) t
      on ((d.start_date >= t.start_date and d.start_date < t.end_date)
          or (d.end_date > t.start_date and d.end_date <= t.end_date))
)
select m.start_date,
       m.end_date,
       m.value,
       l.max_level - m.lvl as depth
  from main_cte m
  cross join max_level_cte l
 where m.rn = 1
 order by m.start_date

如果你可以改变depth的定义，那么我们可以摆脱其中一个CTE：

with date_ranges_cte as (
  select add_months(date '1999-01-01', (rownum-1) * 12) as start_date,
         add_months(date '1999-01-01', rownum * 12) as end_date
    from dual
  connect by rownum <= 7
), main_cte as (
  select d.start_date, 
         d.end_date,
         t.value,
         t.lvl,
         row_number() over (partition by d.start_date, d.end_date order by t.lvl desc, t.id) as rn
    from date_ranges_cte d
    join (select t.*, level as lvl
            from tbl t
           start with parent_id is null
         connect by prior id = parent_id) t
      on ((d.start_date >= t.start_date and d.start_date < t.end_date)
          or (d.end_date > t.start_date and d.end_date <= t.end_date))
)
select start_date,
       end_date,
       value,
       lvl - 1 as depth
  from main_cte
 where rn = 1
 order by start_date

根据时间将行拆分为多行

1 个答案: