我的问题是向here提出问题的后续问题。
功能:
periodic_figure_values()
似乎工作正常,除非被搜索的订单项的名称出现两次。我所指的具体案例是试图获取“长期债务”的数据。上面链接中的函数将返回以下错误:
Traceback (most recent call last):
File "test.py", line 31, in <module>
LongTermDebt=(periodic_figure_values(soup, "Long Term Debt"))
File "test.py", line 21, in periodic_figure_values
value = int(str_value)
ValueError: invalid literal for int() with base 10: 'Short/Current Long Term Debt'
因为它似乎因“短期/当期长期债务”而被绊倒。你看,该页面既有“短期/现期长期债务”和“长期债务”。您可以使用Apple的资产负债表here查看源页面的示例。
我正试图找到一种方法让函数返回“长期债务”的数据,而不会在“短期/当期长期债务”上绊倒。
这是一个功能和一个例子,提取“现金和现金等价物”,工作正常,和“长期债务”,这是行不通的:
import requests, bs4, re
def periodic_figure_values(soup, yahoo_figure):
values = []
pattern = re.compile(yahoo_figure)
title = soup.find("strong", text=pattern) # works for the figures printed in bold
if title:
row = title.parent.parent
else:
title = soup.find("td", text=pattern) # works for any other available figure
if title:
row = title.parent
else:
sys.exit("Invalid figure '" + yahoo_figure + "' passed.")
cells = row.find_all("td")[1:] # exclude the <td> with figure name
for cell in cells:
if cell.text.strip() != yahoo_figure: # needed because some figures are indented
str_value = cell.text.strip().replace(",", "").replace("(", "-").replace(")", "")
if str_value == "-":
str_value = 0
value = int(str_value)
values.append(value)
return values
res = requests.get('https://ca.finance.yahoo.com/q/bs?s=AAPL')
res.raise_for_status
soup = bs4.BeautifulSoup(res.text, 'html.parser')
Cash=(periodic_figure_values(soup, "Cash And Cash Equivalents"))
print(Cash)
LongTermDebt=(periodic_figure_values(soup, "Long Term Debt"))
print(LongTermDebt)
答案 0 :(得分:1)
最简单的方法是使用凸起的try/except
使用 ValueError
组合:
import requests, bs4, re
def periodic_figure_values(soup, yahoo_figure):
values = []
pattern = re.compile(yahoo_figure)
title = soup.find("strong", text=pattern) # works for the figures printed in bold
if title:
row = title.parent.parent
else:
title = soup.find("td", text=pattern) # works for any other available figure
if title:
row = title.parent
else:
sys.exit("Invalid figure '" + yahoo_figure + "' passed.")
cells = row.find_all("td")[1:] # exclude the <td> with figure name
for cell in cells:
if cell.text.strip() != yahoo_figure: # needed because some figures are indented
str_value = cell.text.strip().replace(",", "").replace("(", "-").replace(")", "")
if str_value == "-":
str_value = 0
### from here
try:
value = int(str_value)
values.append(value)
except ValueError:
continue
### to here
return values
res = requests.get('https://ca.finance.yahoo.com/q/bs?s=AAPL')
res.raise_for_status
soup = bs4.BeautifulSoup(res.text, 'html.parser')
Cash=(periodic_figure_values(soup, "Cash And Cash Equivalents"))
print(Cash)
LongTermDebt=(periodic_figure_values(soup, "Long Term Debt"))
print(LongTermDebt)
这个很好地打印出你的数字
请注意,在这种情况下,您并不真正需要re
模块,因为您只检查文字(没有通配符,没有边界)等。
答案 1 :(得分:0)
您可以更改该函数,使其接受正则表达式而不是纯字符串。然后,您可以搜索^Long Term Debt
以确保之前没有任何文字。您需要做的就是改变
if cell.text.strip() != yahoo_figure:
到
if not re.match(yahoo_figure, cell.text.strip()):