Question

我正在尝试学习如何与非官方的xbox api（xboxapi.com）进行交互，但我似乎无法弄清楚如何使用它。文档非常稀缺。这是我最近的（也是我认为最好的）尝试。

<?php
$gamertag = rawurlencode("Major Nelson");

$ch = curl_init("http://www.xboxapi.com/v2/xuid/" . $gamertag);

$headers = array('X-Auth: InsertAuthCodeHere', 'Content-Type: application/json');

curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1 ); # return into a variable
curl_setopt($ch, CURLOPT_HTTPHEADER, $headers ); # custom headers, see above
$xuid = curl_exec( $ch ); # run!
curl_close($ch);

echo $xuid;


?>

运行上述内容后，我获得“301 Moved Permanently”。谁能看到我做错了什么？感谢。

Answer 1

您需要将xuid替换为您的实际xbox个人资料用户ID。另外，使用您的API身份验证代码替换InsertAuthCodeHere。登录到xbox live后，您可以在xboxapi帐户配置文件中找到它们。

请参阅：https://xboxapi.com/v2/2533274813081462/xboxonegames

更新 - Guzzle

我能够使用Guzzle，与http或https一起使用

require __DIR__ . '/vendor/autoload.php';
require_once __DIR__ . '/config.php'; //defines XboxAPI_Key
$gamertag = isset($_GET['gamertag']) ? urldecode($_GET['gamertag']) : 'Major Nelson';
$url = 'http://xboxapi.com/v2/xuid/' . rawurlencode($gamertag);
$guzzle = new GuzzleHttp\Client();
$response = $guzzle->get($url, [
    'headers' => [
        'X-Auth' => XboxAPI_Key,
        'Content-Type' => 'application/json'
    ],
]);
echo $response->getBody(); //2584878536129841

更新2 - cURL

此问题与通过CURLOPT_SSL_VERIFYPEER => false验证SSL证书以及http://www.到https://的重定向有关，该版权已由CURLOPT_FOLLOWLOCATION => true启用

require_once __DIR__ . '/config.php';
$gamertag = isset($_GET['gamertag']) ? urldecode($_GET['gamertag']) : 'Major Nelson';
$url = 'http://www.xboxapi.com/v2/xuid/' . rawurlencode($gamertag);
/**
 * proper url for no redirects
 * $url = 'https://xboxapi.com/v2/xuid/' . rawurlencode($gamertag);
 */
$options = [
    CURLOPT_RETURNTRANSFER => true, // return variable
    CURLOPT_FOLLOWLOCATION => true, // follow redirects
    CURLOPT_AUTOREFERER => true, // set referrer on redirect
    CURLOPT_SSL_VERIFYPEER => false, //do not verify SSL cert
    CURLOPT_HTTPHEADER => [
        'X-Auth: ' . XboxAPI_Key
    ]
]; 
$ch = curl_init($url);
curl_setopt_array($ch, $options);
$content = curl_exec($ch);
echo $content;  //2584878536129841

Answer 2

我得到了答案。我们缺少必需的花括号。工作代码：

$gamertag = rawurlencode("Major Nelson");

$ch = curl_init();
curl_setopt($ch, CURLOPT_URL,"https://xboxapi.com/v2/xuid/{$gamertag}");
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_HTTPHEADER, [
    "X-Auth: InsertAuthCode",
]);

$output = curl_exec($ch);

curl_close ($ch);

print $output;

如何使用PHP和cURL与XBox API进行交互

2 个答案: