Question

我有一个帐户生成器，每次点击“生成”时，都会显示一个新帐户。还有一个“标记为无效”按钮，用于将框中的alt发送到我的管理页面（admin-flagged.php）。

生成器中的代码：

$result = mysqli_query($con, $generatorquery) or die(mysqli_error($con));
while ($row = mysqli_fetch_array($result)) {
    echo '
      <div class="col-lg-4">
          <!--user info table start-->
          <section class="panel">
              <div class="panel-body">
                  <div class="task-thumb-details">
                      <h1>'.$row['name'].' Generator</h1>
                  </div>
                  <legend></legend>
                  <input type="text" id="generator'.$row["id"].'" onclick="select_all(this)" class="text-center form-control" placeholder="username:password"></br>
                  <button id="generate'.$row["id"].'" class="btn btn-info btn-block">Generate</button></br>
                  <legend></legend>
                  <form id="flagform'.$row["id"].'" action="generator.php" method="POST">
                      <input type="hidden" id="flag'.$row["id"].'" name="flagalt" value="">
                      <input type="hidden" name="generator" value="'.$row["id"].'">
                      <div class="btn-group btn-group-justified">
                          <a id="copy'.$row["id"].'" data-clipboard-target="generator'.$row["id"].'" title="Copy" class="btn btn-success">Copy</a>
                          <a href="javascript:void(0);" onclick=$(this).closest("form").submit(); title="Flag as invalid" class="btn btn-danger">Flag as invalid</a>
                      </div>
                  </form>
              </div>
          </section>

管理页面中的代码：

<?php
    $result = mysqli_query($con, "SELECT * FROM `generators`") or die(mysqli_error($con));
    while ($row = mysqli_fetch_array($result)) {
        $generator = $row['name'];
        $generatorid = $row['id'];
        $result2 = mysqli_query($con, "SELECT * FROM `generator$generatorid` WHERE `status` = '2'") or die(mysqli_error($con));
        while ($row2 = mysqli_fetch_array($result2)) {
            echo '<tr>
              <td>' . $generator . '</td>
              <td>'.$row2['alt'].'</td>
              <td><a class="btn btn-info btn-xs" href="#" disabled><i class="icon-check"></i> Test Alt</a></td>
              <td><a class="btn btn-danger btn-xs" href="admin-flagged.php?delete=' . $row2['id'] . '&generator='.$generatorid.'"><i class="icon-trash "></i></a></td>
          </tr>
        ';
        }
    }
?>

管理页面顶部的PHP代码：

if (isset($_GET['delete']) && isset($_GET['generator'])){
    $id = mysqli_real_escape_string($con, $_GET['delete']);
    $generatorid = mysqli_real_escape_string($con, $_GET['generator']);
    mysqli_query($con, "UPDATE `generator$generatorid` SET `status` = '0' WHERE `id` = '$id'") or die(mysqli_error($con));
    echo '
        <script>
            window.history.replaceState("object or string", "Title", "/admin-flagged.php");
        </script>
    ';
}

PhpMyAdmin表：

`-- Table structure for table `generator3`
--

CREATE TABLE IF NOT EXISTS `generator3` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `alt` varchar(1000) DEFAULT NULL,
  `status` int(1) DEFAULT '1',
  PRIMARY KEY (`id`)
) ENGINE=MyISAM  DEFAULT CHARSET=utf8 AUTO_INCREMENT=997 ;

--
-- Dumping data for table `generator3`
--

INSERT INTO `generator3` (`id`, `alt`, `status`) VALUES
(505, 'psharma078@gmail.com:pinju337\r', 1);`

标记为无效;按钮不起作用

0 个答案: