Question

我想通过一些独立的例程以顺序方式显示文件分析的进度状态，因为每个分析例程都需要一些时间。附带的演示代码显示了我遇到的问题。问题是分析结束后显示只会更新？欣赏知道为什么代码没有做什么以及如何解决它。注意：例程1＆amp; 2在2个单独的.py文件中。

from Tkinter import *
import tkFileDialog
import tkMessageBox
import routine1
import routine2
import sys

class Analysis(Frame):
   def __init__(self):
      Frame.__init__(self)
      self.text = Text(self, height=20, width=60) # 20 characters
      self.pack()

      scroll=Scrollbar(self)
      scroll.pack(side=RIGHT, fill=Y)
      scroll.config(command=self.text.yview)
      self.text.config(background='white')
      self.text.pack(expand=YES, fill=BOTH)


   def selectfile(self):
      fname = tkFileDialog.askopenfilename()
      self.text.delete(1.0, END)
      self.text.insert(INSERT, ' working on routine 1: \n')
      routine1.main(fname)
      self.text.insert(INSERT, ' routine 1 done: \n')
      self.text.insert(INSERT, ' working on routine 2: \n')
      routine2.main(fname)
      self.text.insert(INSERT, ' routine 2 done: ')
      sys.exit()

def main():
    tk = Tk()
    tk.title('Data Analysis')

    atext = Analysis()
    atext.pack()
    open_button = Button(tk, text="Select Data",
    activeforeground='blue', command=atext.selectfile)
    open_button.pack()

    message='''
    Select file to be analysized
    '''
    atext.text.insert(END,message)
    tk.mainloop()

if __name__ == "__main__":
   main()

routine1.py

import time
def main(Filename):
   print Filename
   time.sleep(1) # to simulate process time
   return

routine2.py

import time
def main(Filename):
   print Filename
   time.sleep(1) # to simulate process time
   return

Answer 1

您需要在更改GUI中的内容后通过调用update_idletasks() universal widget method手动更新显示。请注意，上次更新只会在很短的时间内显示，因为紧随其后会发出sys.exit()来电。

   def selectfile(self):
      fname = tkFileDialog.askopenfilename()

      self.text.delete(1.0, END)
      self.text.insert(INSERT, ' working on routine 1: \n')
      self.text.update_idletasks()
      routine1.main(fname)
      self.text.insert(INSERT, ' routine 1 done: \n')
      self.text.update_idletasks()

      self.text.insert(INSERT, ' working on routine 2: \n')
      self.text.update_idletasks()
      routine2.main(fname)
      self.text.insert(INSERT, ' routine 2 done: ')
      self.text.update_idletasks()
      sys.exit()

Tkinter文本未按顺序显示

1 个答案: