编译错误:在此上下文中无法隐式捕获“this”

时间:2016-07-26 16:57:36

标签: c++ scope this condition-variable

我试图添加一个condition_variable来处理线程,但在这一行得到一个编译错误:

this->cv.wait(lk, []{return this->ready;});

看起来对于变量this-> ready,'this'不在正确的范围内。

在Java中,可以使用TestThread来处理这个问题。在C ++中有什么做同样的事情吗?

void TestThread::Thread_Activity()
    {
        std::cout << "Thread started \n";
        // Wait until ThreadA() sends data
        {
            std::unique_lock<std::mutex> lk(m);
            this->cv.wait(lk, []{return ready;});
        }

        std::cout << "Thread is processing data\n";
        data += " after processing";
        // Send data back to ThreadA through the condition variable
        {
           // std::lock_guard<std::mutex> lk(m);
            processed = true;
           // std::cout << "Thread B signals data processing completed\n";
        }

    }

1 个答案:

答案 0 :(得分:27)

您需要捕获this指针:

this->cv.wait(lk, [this]{return ready;});