两个SELECT里面的NOT IN echo array（）mysql php，一个SELECT IS OK

Question

我的代码只有在NOT IN中删除一个（SELECT）时才能正常，如果我在NOT IN中添加两个（SELECT），它就是echo array（）;首先，我想获得val =那些值和mark ='major'的果实。然后我想要删除任何标记='age'或mark ='ripe'的水果，所以我使用OR fruit NOT IN。我已经检查了NOT IN中的SELECT，当它们独自时它是可以的。

<?php
$dia = $wpdb->get_results( $wpdb->prepare("
			SELECT fruit FROM table WHERE val IN (%s,%s,%s) AND mark = 'major' OR fruit NOT IN (
(SELECT fruit FROM table WHERE cat='uncommon' AND val = %s AND mark='age'), 
(SELECT fruit FROM table WHERE cat='uncommon' AND val = %s AND mark='ripe')) GROUP BY fruit
			",$sym1,$sym2,$sym3,$age,$ripe));



?>

Answer 1

你不需要两个查询，你只需要改变你的条件。变化：

(SELECT fruit FROM table WHERE cat='uncommon' AND val = %s AND mark='age')

要：

(SELECT fruit FROM table WHERE cat='uncommon' AND (val = %s AND mark='age') OR (val = %s AND mark='ripe'))

否则您需要汇总查询。