Question

以下是我正在使用的代码：

-(void)viewDidLoad
{
    NSString *checkerPath = [[NSBundle mainBundle] pathForResource:@"black-yellow-checker" ofType:@"png"];
    UIImage *checkerImage = [[UIImage alloc] initWithContentsOfFile:checkerPath];
    checkerView = [[UIImageView alloc] initWithFrame:CGRectMake(0.0f, 230.0f, 320.0f, 280.0f)];
    [checkerView setImage:checkerImage];

    UIButton *backButton = [[UIButton buttonWithType:UIButtonTypeCustom] retain];
    backButton.frame = CGRectMake(45.0f, 175.0f, 230.0f, 50.0f);
    [backButton setBackgroundImage:[UIImage imageWithContentsOfFile:[[NSBundle mainBundle] pathForResource:@"yellowButton" ofType:@"png"]] forState:UIControlStateNormal];
    [backButton addTarget:self action:@selector(goBackHome:) forControlEvents:UIControlEventTouchDown];
    [backButton setTitle:@"Back" forState:UIControlStateNormal];
    backButton.titleLabel.font = [UIFont fontWithName:@"Marker Felt" size:30];
    backButton.titleLabel.textColor = [UIColor blackColor];
    [checkerView addSubview:backButton];
}

- (void)goBackHome:(id)sender
{
    NSLog(@"go back pressed");
}

不确定为什么这不起作用。按钮出现，但是当我按下按钮时没有任何反应。当我触摸它时，它甚至不会改变为“缩进”图像。没有。不能使用IB，必须以编程方式。有什么想法吗？

Answer 1

UIImageView has userInteractionEnabled set to NO by default。这可以防止任何子视图被触及。

您可以通过

启用图像视图的用户交互

checkerView.userInteractionEnabled = YES;

或创建新的UIView以同时包含checkerView和backButton。

UIView* newView = ...
...
[newView addSubview:checkerView];
[newView addSubview:backButton];

Answer 2

我相信forControlEvents：必须是UIControlEventTouchUpInside。

无法以编程方式使UIButton工作 - iPhone

2 个答案: