Question

如何在JSON文件中计算出一个名称的出现次数。我想知道多少次，让我们说名字＆＃34; MICO＆＃34;，出现在JSON文件中，我想把它存储在像var mico=2;这样的变量中。我的JSON文件如下所示：

[
 {
    "igralec1": "LEON",
    "datum": "Cetrtek - 21. Julij 2016",
    "set1": "4",
    "set2": "6",
    "set3": "6",
    "set4": "-",
    "set5": "-",
    "igralec2": "MICO",
    "set21": "6",
    "set22": "1",
    "set23": "4",
    "set24": "-",
    "set25": "-"
},
{
    "igralec1": "MICO",
    "datum": "Ponedeljek - 11. Julij 2016",
    "set1": "6",
    "set2": "6",
    "set3": "6",
    "set4": "-",
    "set5": "-",
    "igralec2": "PERO",
    "set21": "2",
    "set22": "1",
    "set23": "3",
    "set24": "-",
    "set25": "-"
  }
]

Answer 1

假设已经（以某种方式）将JSON检索到名为json的变量中，您必须解析它以获取数组：

var array = JSON.parse(json);

虽然如果您使用jQuery Ajax方法来获取它，jQuery可能会为您解析它，那么您可以跳过该步骤。无论如何，假设解析数据在（{1}}变量中是（某种方式）：

array

演示：https://jsfiddle.net/rzmada6p/1/

我使用了两个function searchForWord(word, array) { return array.reduce(function(s, o) { if (o.igralec1 === word) s++; if (o.igralec2 === word) s++; return s; }, 0); } var micoCount = searchForWord("MICO", array); // 2 var peroCount = searchForWord("PERO", array); // 1语句，以防同一对象中的if和igralec1属性都包含您要查找的字词。如果您知道它只会是任何给定对象中的一个或另一个属性，那么您可以使用一个igralec2和一个或：

if

进一步阅读：the array .reduce() method。

Answer 2

使用RegExp构造函数和String.match函数的解决方案：

var jsonData= '[{"igralec1": "LEON","datum":"Cetrtek - 21. Julij 2016","set1": "4","set2": "6","set3": "6","set4": "-","set5": "-","igralec2": "MICO","set21": "6","set22": "1","set23": "4","set24": "-","set25": "-"},{"igralec1": "MICO","datum": "Ponedeljek - 11. Julij 2016","set1": "6","set2": "6","set3": "6","set4": "-","set5": "-","igralec2": "PERO","set21": "2","set22": "1","set23": "3","set24": "-","set25": "-"}];';

var getCount = function(jsonData, str){
        var re = new RegExp('\"' + str +'\"', "ig");
        return jsonData.match(re).length;
    };

console.log(getCount(jsonData, "MICO"));  // 2
console.log(getCount(jsonData, "LEON"));  // 1

Answer 3

function count(data, entry) {
    return data
               .map(obj => 
                   Object
                       .keys(obj)
                       .map(key => obj[key])
                       .filter(item => item === entry)
                       .length)
               .reduce((res, val) => res + val, 0);
}

用法：

const data = []; // your array here
console.log(count(data, 'MICO')); // 2

如果你知道钥匙：

function count(data, keys, entry) {
    return data1
               .reduce((res, obj) => 
                   keys.forEach(key => obj[key] === entry && res++) || res, 0);
}

用法：

const data = []; // your array here
console.log(count(data, ['igralec1', 'igralec2'], 'MICO')); // 2

注意它使用es2015。

Answer 4

您可以使用Jquery grep函数。示例代码将如下所示。我假设您的JSON数组名称是arr Working code

    var array = [
 {
    "igralec1": "LEON",
    "datum": "Cetrtek - 21. Julij 2016",
    "set1": "4",
    "set2": "6",
    "set3": "6",
    "set4": "-",
    "set5": "-",
    "igralec2": "MICO",
    "set21": "6",
    "set22": "1",
    "set23": "4",
    "set24": "-",
    "set25": "-"
},
{
    "igralec1": "MICO",
    "datum": "Ponedeljek - 11. Julij 2016",
    "set1": "6",
    "set2": "6",
    "set3": "6",
    "set4": "-",
    "set5": "-",
    "igralec2": "PERO",
    "set21": "2",
    "set22": "1",
    "set23": "3",
    "set24": "-",
    "set25": "-"
  }
];
var MICO=0;
 var objJson = jQuery.grep(array, function( n, i ) {    
      if(n.igralec1=="MICO" || n.igralec2 =="MICO"){
          MICO++;
        }
    });
     alert(MICO);

计算json文件中的名称出现次数

4 个答案: