打印2个数字之间的范围

Question

我有这段代码可以找到两个数字之间的差距：

;WITH
cte AS (
SELECT
    BSEG_BELNR, 
    RowNum = ROW_NUMBER() OVER (ORDER BY BSEG_BELNR)
FROM dbo.QLIK_JOURNAL GROUP BY BSEG_BELNR),
cte2 AS (
SELECT *, DENSE_RANK() OVER (ORDER BY BSEG_BELNR - RowNum) AS Series 
FROM cte),
cte3 AS (
SELECT *, COUNT(*) OVER (PARTITION BY Series) AS SCount 
FROM cte2),
cte4 AS (
SELECT
    MinID = MIN(BSEG_BELNR), 
    MaxID = MAX(BSEG_BELNR), 
    Series
FROM cte3
GROUP BY Series)
 SELECT a.MaxID,b.MinID
 FROM cte4 a
INNER JOIN cte4 b
    ON a.Series+1 = b.Series
    ORDER BY a.MaxID

并且此代码提供了2列，但我需要打印不同的我意味着差距不是开始和结束。

MaxID          MinID    
-----------------------
0000015010    0000015012
0000015018    0000015020
0000015020    0000015022
0000015041    0000015043
0000015062    0000015065
........      ........

我希望在

之间打印数字

  Gap
---------
0000015011
0000015019
0000015021
0000015042
0000015063
0000015064

我在SQL SERVER中如何做到这一点

Answer 1

您可以使用CTE并转换为int：

;WITH cte AS (
SELECT  MIN(CAST(MaxID as int)) as Mi,
        MAX(CAST(MinID as int)) as Ma
FROM YourResultSet c
UNION ALL
SELECT  Mi + 1,
        Ma
FROM cte
WHERE Mi < Ma
)

SELECT STUFF(c.Mi,1,0,'00000')
FROM cte c
INNER JOIN YourResultSet  y
    ON c.Mi > CAST(MaxID as int) and c.Mi < CAST(MinID as int)

输出：

0000015011
0000015019
0000015021
0000015042
0000015063
0000015064

Answer 2

我想要返回MaxID和MinID列之间的值之间的差距，请尝试：

why the data not divided into same 4 block of 50MB in order to save them each one of them in 64MB of block size.