Question

当我尝试使用此代码时，它会显示错误：

您的SQL语法有错误;检查与您的MySQL服务器版本相对应的手册，以便在{＆lt; INSERT INTO notifications附近使用正确的语法（title，date，group_id，owner_id）VALUES（＆＃39; Een nie＆＃39; at line 1

$date = time();
$gid = 123;
$q = "INSERT INTO `notifications` (title,date,group_id,owner_id) VALUES ";

$zw = mysqli_query($database->connection,"SELECT `owner_id` FROM `joins` WHERE `group_id` = '$gid'");
$ch = mysqli_num_rows($zw);
while($gg = mysqli_fetch_array($zw))
{
  $owner_idd = $gg['owner_id'];
  $q .= "('xxxxxEen nieuwe aanbieding voor groep     $gid','$date','$gid','$owner_idd'),";
}

$q .= rtrim($q,',');


mysqli_query($database->connection, $q) or die (mysqli_error($database->connection));

错误在哪里？

Answer 1

试试（使用PDO你可以把它改成mysqli _）：

<强>的index.php

<?php

$pdo = new PDO('mysql:host=localhost;dbname=test', 'root', '', array(
    PDO::MYSQL_ATTR_INIT_COMMAND => "SET NAMES utf8"
        ));
$pdo->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$date = time();
$gid = 2;
$sth = $pdo->prepare("SELECT * FROM joins WHERE `group_id` = '$gid'");
$sth->execute();
$data = $sth->fetchAll(PDO::FETCH_ASSOC);
$values = array();
if (count($data)) {
    foreach ($data as $dataIndex => $dataValue) {
        $values[] = "('title','$date'," . implode(",", array_values($dataValue)) . ")";
    }
    $values = implode(",", $values);
    $insert = "INSERT INTO notifications (title,date,group_id,owner_id) VALUES $values";
    $sth = $pdo->prepare($insert);
    $sth->execute();
}

通知表创建：

CREATE TABLE `notifications` (
    `id` INT(11) NOT NULL AUTO_INCREMENT,
    `title` VARCHAR(255) NOT NULL DEFAULT '0',
    `date` INT(11) NOT NULL DEFAULT '0',
    `group_id` INT(11) NOT NULL DEFAULT '0',
    `owner_id` INT(11) NOT NULL DEFAULT '0',
    PRIMARY KEY (`id`)
)
COLLATE='utf8_general_ci'
ENGINE=InnoDB;

加入表格创建：

CREATE TABLE `joins` (
    `group_id` INT(11) NULL DEFAULT NULL,
    `owner_id` INT(11) NULL DEFAULT NULL,
    INDEX `group_id` (`group_id`),
    INDEX `owner_id` (`owner_id`)
)
COLLATE='utf8_general_ci'
ENGINE=InnoDB;

Answer 2

根据您的mysql查询错误消息＆＃34;＆＃39; INSERT INTO通知（title，date，group_id，owner_id）VALUES（＆＃39; Een nie＆＃39;在第1行和第34行; 单引号创建问题。

在将数据推送到插入查询之前，尝试添加mysqli_real_escape_string（$ con，＆＃34; dd＆＃39; sdfsdfsdf＆＃34;）。

mysql在一个查询中使用while循环插入多行

2 个答案: