iOS：二元运算符＆＃39; | =＆＃39;不能适用于两个Bool＆＃39;操作数

Question

在对两个布尔值执行按位运算时出错。 错误：＆＃34;二元运算符＆＃39; | =＆＃39;不能适用于两个Bool＆＃39;操作数＆＃34;

func checkAvailability(available:Bool) -> Bool{
    var bChanged = false
    bChanged |= available //"Binary operator '|=' cannot be applied to two 'Bool' operands"
    return bChanged  
}

请任何人帮我解决问题......

Answer 1

您可以通过重载运算符来自己定义：

斯威夫特2：

func |= (inout left: Bool, right: Bool) {
   left = left || right
}

斯威夫特3：

func |= (left: inout  Bool, right: Bool) {
   left = left || right
}

Answer 2

这是Lew回答的简单扩展，包括其他两个“缺失”的运营商。

// A couple of operators that exist in C# and Java but are missing from Swift.

public func |= (leftSide : inout Bool, rightSide : Bool) {
   leftSide = leftSide || rightSide
}

public func &= (leftSide : inout Bool, rightSide : Bool) {
   leftSide = leftSide && rightSide
}

public func ^= (leftSide : inout Bool, rightSide : Bool) {
   leftSide = leftSide != rightSide
}