Question

基本上两个表工作我想选择一个头值来对付它的id从第二个表中收集所有数据而不是第二个头值对它的id收集所有数据......我的问题是从头表中收集值时并且它的id收集来自第二个表的所有值，但是头部值一次又一次地重复对着while循环中的第二个表值

<?php
$result = mysql_query("SELECT * 
            FROM account_head
            LEFT JOIN account_head_name
            ON account_head.ID = account_head_name.account_head_ID ");
while($array=mysql_fetch_array($result))
{
    if($array > 0)
    {
        ?>

        <b><?php echo $array['Name'] ; ?> </b>
        <br>
        <?php echo $array['name'] ; ?>
        <br>

        <?php
    }
}

Answer 1

可能你必须写：

 if(count($array) > 0)

Answer 2

In one - many relation the best way to get data is make two queries

$result = mysql_query("SELECT * 
            FROM account_head");
while($array=mysql_fetch_array($result))
{
   ?>
       <b>Head Name:<?php echo $array['Name'] ; ?> </b>
   <?php 
    $result1 = mysql_query("SELECT * 
            FROM account_head_name where account_head_ID = $array['ID'] ");
     while($array1=mysql_fetch_array($result1))
    ?>


        <br>
        <?php echo $array1['name'] ; ?>
        <br>

        <?php
   }

}

Note: Better to avoid mysql function Use mysqli。

头表值不重复

2 个答案: