我有跟随json字符串（这是它的一部分）。
SELECT
COUNT(*) AS total
FROM
( SELECT ADDDATE('2016-07-01', INTERVAL @i:=@i+1 DAY) AS DAY
FROM (
SELECT a.a
FROM (SELECT 0 AS a UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) AS a
CROSS JOIN (SELECT 0 AS a UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) AS b
CROSS JOIN (SELECT 0 AS a UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) AS c
) a
JOIN (SELECT @i := -1) r1
WHERE
@i < DATEDIFF('2016-08-01', '2016-07-01')
) AS dateTable
WHERE WEEKDAY(dateTable.Day) IN (5,6)
如何使用newtonsoft .json或任何其他方式从此字符串中获取值（单独的对象和值）。
我尝试过这样做（通过创建根对象，只需一点点尝试）
var cheerText = cheerio.load(res.text);
cheerText('#topic_list .topic_title').each(function (idx, element) {
var element = cheerText(element);
var href = url.resolve(cnodeUrl, element.attr('href'));
topicUrls.push(href);
});
然后像这样调用它
[
{
"$id": "1",
"topdealMaster": [
{
"$id": "2",
"topdeal_id": 27,
"calling_number": "12345678",
"whats_include": "fssdf\nsdfsd",
"child_policy": "sdfsdf\nsdf\nsdfsd",
"optional_extras": "sdfsd\nsdfsd",
"fine_prints": "sdfsdf\nsdf",
"prices_id": "54,55,52,53,",
"hotels_id": "2086,2086,",
"cruise_id": "23,",
"tour_id": "28,27,",
"deal_id": 20224,
"created_user_id": 28,
"created_datetime": null,
"last_modified_user_id": null,
"last_modified_datetime": null,
"isActive": null,
"employee_master": null,
"deal_master": {
"$id": "3",
"deal_id": 20224,
"our_deal_code": "TCTZ00021",
"deal_code": "TCTZ00021",
"deal_company_id": null,
"deal_title": "Thasnen testing",
"created_user_id": null,
"created_time": null,
"isAlwaysOn": null,
"isActive": null,
"activated_user_id": null,
"activated_time": null,
"extra_info": null,
"deal_type_id": "TCTZ",
"min_price": null,
"save_up": null,
"fine_prints": null,
"acco_type_id": null,
"deal_hotel_id": null,
"no_of_nigths": null,
"airport_code": null,
"deal_comments": [],
"deal_fares": [],
"deal_other_company_hotel": null,
"topdeal_master": []
}
}
],
"topDealHotel": [
{
"$id": "4",
"Deal_Hotel_Id": 2086,
"Deal_Hotel_Name": "The Ocean Colombo",
"Created_Emp_Id": 108,
"Updated_Emp_Id": 28,
"Updated_Time": null,
"System_Date_Time": "2016-06-20T10:11:19.037",
"City_Code": "CMB",
"Latitude": 6.88531,
"Longitude": 79.855195,
"LocationId": 6887404,
"Hotel_Amentities": [
{
"$id": "5",
"id": 0,
"hotel_amenity_id": 2,
"amenity_type": "24-hour front desk",
"image_path": "fa fa-square"
},
{
"$id": "6",
"id": 0,
"hotel_amenity_id": 3,
"amenity_type": "Airport transportation",
"image_path": "fa fa-square"
},
{
"$id": "7",
"id": 0,
"hotel_amenity_id": 8,
"amenity_type": "Bar/lounge",
"image_path": "fa fa-square"
},
{
"$id": "8",
"id": 0,
"hotel_amenity_id": 9,
"amenity_type": "Breakfast available (surcharge)",
"image_path": "fa fa-square"
},
{
"$id": "9",
"id": 0,
"hotel_amenity_id": 10,
"amenity_type": "Business center",
"image_path": "fa fa-square"
},
{
"$id": "10",
"id": 0,
"hotel_amenity_id": 16,
"amenity_type": "Dry cleaning/laundry service",
"image_path": "fa fa-square"
},
{
"$id": "11",
"id": 0,
"hotel_amenity_id": 17,
"amenity_type": "Elevator/lift",
"image_path": "fa fa-square"
},
{
"$id": "12",
"id": 0,
"hotel_amenity_id": 22,
"amenity_type": "Free newspapers in lobby",
"image_path": "fa fa-square"
},
{
"$id": "13",
"id": 0,
"hotel_amenity_id": 23,
"amenity_type": "Free WiFi",
"image_path": "fa fa-square"
},
{
"$id": "14",
"id": 0,
"hotel_amenity_id": 32,
"amenity_type": "Limo or Town Car service available",
"image_path": "fa fa-square"
},
{
"$id": "15",
"id": 0,
"hotel_amenity_id": 33,
"amenity_type": "Luggage storage",
"image_path": "fa fa-square"
},
{
"$id": "16",
"id": 0,
"hotel_amenity_id": 39,
"amenity_type": "Restaurant",
"image_path": "fa fa-square"
},
{
"$id": "17",
"id": 0,
"hotel_amenity_id": 43,
"amenity_type": "Smoke-free property",
"image_path": "fa fa-square"
}
],
"Room_Amentities": [
{
"$id": "18",
"id": 0,
"room_amenity_id": 2,
"amenity_type": "Air conditioning",
"ImagePath": "fa fa-square"
},
{
"$id": "19",
"id": 0,
"room_amenity_id": 4,
"amenity_type": "Blackout drapes/curtains",
"ImagePath": "fa fa-square"
},
并试着这个，打电话到上课。
public class RootobjectOne
{
[JsonProperty("topdealMaster")]
public TopdealMaster TopdealMaster { get; set; }
}
public class TopdealMaster
{
[JsonProperty("topdeal_id")]
public string topdealId {get;set;}
}
但没有取得任何成功的结果。请帮助。
注意：它会出现以下错误-----＆gt;因为类型需要JSON对象（例如{＆＃34; name＆＃34;：＆＃34; value＆＃34;}）才能正确反序列化。 要修复此错误，请将JSON更改为JSON对象（例如{＆＃34; name＆＃34;：＆＃34; value＆＃34;}）或将反序列化类型更改为实现集合接口的数组或类型（例如ICollection，IList）就像可以从JSON数组反序列化的List。 JsonArrayAttribute也可以添加到类型中以强制它从JSON数组反序列化。
答案 0 :(得分：1)
你在顶级有一个数组，所以它应该是：
var items = JsonConvert.DeserializeObject<List<RootobjectOne>>(b);
同样"topdealMaster"是一个数组，所以根类应该是这样的：
public class RootobjectOne
{
[JsonProperty("topdealMaster")]
public Topdealmaster[] TopdealMasters { get; set; }
}