我有像这样的对象数组
var result={
"employees": [
{
"_id": "5796e7a27d075bd0453b7751",
"firstName": "Test4",
"schemaName": "Employee"
},
{
"_id": "5796e78e7d075bd0453b774f",
"firstName": "Test 3",
"schemaName": "Employee"
},
{
"_id": "5790b203df5ad69025e8a20b",
"email": "df@gmail.com",
"schemaName": "Employee"
},
{
"_id": "577f69cc789df5ec1e995513",
"firstName": "Jeevan",
"email": "ddd@asd.com",
"schemaName": "Employee"
},
{
"_id": "577f69cc789df5ec1e995513",
"firstName": "Chethan",
"email": "ddd@asd.com",
"schemaName": "Employee"
}
]
};
};
但我希望通过电子邮件发送uniq对象。我正在使用lodash uniq,但它没有给出正确的结果。在这里我试过这段代码。
var combined=result.employees.map(function(employee){
employee.schemaName='Employee';
return employee;
});
combined = _.uniq(combined, 'email');
console.log(combined);
结果是这样的。
[ { _id: '5796e7a27d075bd0453b7751',
firstName: 'Test4',
schemaName: 'Employee' },
{ _id: '5790b203df5ad69025e8a20b',
email: 'df@gmail.com',
schemaName: 'Employee' },
{ _id: '577f69cc789df5ec1e995513',
firstName: 'Jeevan',
email: 'ddd@asd.com',
schemaName: 'Employee' } ]
我想要没有电子邮件ID的对象,而且我只想要唯一的邮件ID对象,任何人都可以帮助我。我希望结果包含没有电子邮件ID的对象。结果应该是这样的。
[ { _id: '5796e7a27d075bd0453b7751',
firstName: 'Test4',
schemaName: 'Employee' },
{ _id: '5796e78e7d075bd0453b774f',
firstName: 'Test3',
schemaName: 'Employee' },
{ _id: '5790b203df5ad69025e8a20b',
email: 'df@gmail.com',
schemaName: 'Employee' },
{ _id: '577f69cc789df5ec1e995513',
firstName: 'Jeevan',
email: 'ddd@asd.com',
schemaName: 'Employee' } ]
答案 0 :(得分:3)
这也可以成功。
_.uniqBy(result.employees, function(employee){return employee.email || employee._id;});
答案 1 :(得分:2)
我建议您使用自己的比较器来使用_.uniqWith。
var result = {
"employees": [
{
"_id": "5796e7a27d075bd0453b7751",
"firstName": "Test4",
"lastName": "T",
"__v": 0,
"schemaName": "Employee"
},
{
"_id": "5796e78e7d075bd0453b774f",
"firstName": "Test 3",
"lastName": "T",
"__v": 0,
"schemaName": "Employee"
},
{
"_id": "5796e77e7d075bd0453b774d",
"firstName": "Test 2",
"lastName": "T",
"__v": 0,
"documents": [],
"schemaName": "Employee"
},
{
"_id": "5796e7707d075bd0453b774b",
"firstName": "Test1",
"lastName": "T",
"__v": 0,
"schemaName": "Employee"
},
{
"_id": "5790b203df5ad69025e8a20b",
"firstName": "Ganesh",
"lastName": "dsf",
"__v": 0,
"email": "df@gmail.com",
"schemaName": "Employee"
},
{
"_id": "577f69cc789df5ec1e995513",
"firstName": "Jeevan",
"__v": 0,
"email": "fs@asf.com",
"schemaName": "Employee"
},
{
"_id": "577f69cc789df5ec1e995513",
"firstName": "Chethan",
"__v": 0,
"email": "fs@asf.com",
"schemaName": "Employee"
}
]
};
// Create a lodash chain from the employees.
combined = _.uniqWith(result.employees, function(e1, e2){
return e1.email && e1.email === e2.email;
});
console.log(combined);
<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.14.0/lodash.min.js"></script>
答案 2 :(得分:0)
我正在使用deepEquals
算法,因此该代码变得更加通用。如果您只想通过电子邮件检查,只需更改下面的equals
功能。
const equals =
// Naïve deepEquals, only for demo. Doesn't work if keys orders vary.
(obj1, obj2) => JSON.stringify(obj1) === JSON.stringify(obj2);
// A real deepEquals:
// https://www.npmjs.com/package/fast-deep-equal
const uniq = (el1, index1, array) =>
array.every((el2, index2) => index1 <= index2 || !equals(el1, el2));
[{ a: 1, b: 2 }, { c: 3 }, { a: 1, b: 2 }, { d: 4 }, { a: 1, b: 2 }].filter(uniq);
// Result: [ { a: 1, b: 2 }, { c: 3 }, { d: 4 } ]