我在此示例中花了一个时间,每次我从此代码中获得Unable to read cin
ios_base::iostate
等于failbit
的错误:
#include "dates.h"
#include <iostream>
#include <ctime>
#include <locale>
#include <sstream>
#include <iterator>
using namespace std;
void trasnlateDate(istream&in, ostream&out){
const time_get<char>& dateReader = use_facet<time_get<char> >(in.getloc());
ios_base::iostate state = static_cast<ios_base::iostate>(0);
istreambuf_iterator<char> end;
tm t;
dateReader.get_date(in, end, in, state, &t);
if(state == static_cast<ios_base::iostate>(0) || state == ios_base::eofbit){
const time_put<char>& dateWriter = use_facet<time_put<char> >(out.getloc());
char fmt[] = "%x";
if(dateWriter.put(out, out, out.fill(), &t, &fmt[0], &fmt[2]).failed())
cerr << "unable to write to output stream.\n";
}else{
cerr << "Unable to read cin.\n";
}
}
int main(){
locale::global(locale(""));
cin.imbue(locale("en_US.utf8"));
cout.imbue(locale("de_DE.utf8"));
trasnlateDate(cin, cout);
}
一如既往,Ubuntu 10.4 x64中的gcc 4.4.3
答案 0 :(得分:4)
我在一个盒子上运行了你的示例代码,直到我输入02/02/2005的输入,它就像你说的那样失败了。
看起来像月和日字段中的前导零是必要的。