Question

我有一个查询，我可以在shell中运行，并根据我的模型和关系的工作方式得到正确的答案：

# And let's see each business's employees:
employees=Employee.objects.filter(business_locations__business=business).distinct()

这很有效，我可以将其设置为员工并让所有为企业工作的员工。麻烦的是，在尝试实际使用此模型并从中呈现列表视图时，我不确定这是一个干净的方法。如果您看到list.html代码（最后一个代码段），您可以看到我尝试在列表中提供为企业工作的员工数量，然后理想情况下提供使用<-- --> arrow widget thingy编辑员工的链接。

我知道我必须在下面的视图中这样做，但我不确定最干净的方式。最好的我可以想出一个for循环和一个id的地图？

我有一个view方法：在我的views.py中：

def business_list(request):
    object_list = Business.objects.all()
    paginator = Paginator(object_list, 25) # 3 posts in each page
    page = request.GET.get('page')
    #make a map into the object list some how so I can have this data at the end...


    try:
        business = paginator.page(page)
    except PageNotAnInteger:
        # If page is not an integer deliver the first page
        business = paginator.page(1)
    except EmptyPage:
        # If page is out of range deliver last page of results
        business = paginator.page(paginator.num_pages)

    return render(request, 'ipaswdb/group/list.html', {'page':page, 'business':business, 'object_list':object_list})

然后我对该视图的渲染视图模板就是这个list.html：

{% extends "ipaswdb/base.html" %}

{% block title %}Businesses{% endblock %}

{% block content %}

    <h1>Businesses</h1> <p> Search: </p>

    {% with object_list.count as total_businesses %}
            <h2>
         There are {{ total_businesses }}  businesses
            </h2>
    {% endwith %}
    <table class="table">
    <tr>
        <th> ID</th>
        <th> Business Name</th>
        <th> Comments</th>
        <th> Total employees</th>
        <th>Edit</th>
        <th>Term</th>

    {% for group in groups %}
        <tr>
            <td><a href="{{ business.id }}">{{ business.id }}</a></td>
            <td><a href="{{ business.id }}">{{ business.business_name }}</a></td>
            <td> {{ business.notes|truncatewords:30|linebreaks }}</td>
<!-- How do i do this? -->
            <td><a href="linktoaddremoveemployeestoabusiness"> {{ business.business_total }}</a></td> 
            <td> editbutton</td>
            <td>termbutton</td>

        </tr>
    {% endfor %}
    </table>
    {% include "pagination.html" with page=groups %}

{% endblock %}

型号：

class Employee(models.Model):
        first_name = models.CharField(max_length = 50)
        business_locations = models.ManyToManyField('BusinessLocations', through='EmployeeLocations')


class EmployeeLocations(models.Model):
    employee = models.ForeignKey('Employee', on_delete=models.CASCADE)
    business_location = models.ForeignKey('BusinessLocations', on_delete=models.CASCADE)
    created_at=models.DateField(auto_now_add=True)
    updated_at=models.DateField(auto_now=True)
    def __str__(self):
        return self.provider.first_name

class BusinessLocations(models.Model):
    address = models.ForeignKey('Address', on_delete= models.SET_NULL, null=True)
    business = models.ForeignKey('Business', on_delete=models.CASCADE)
    doing_business_as = models.CharField(max_length = 255)
    created_at=models.DateField(auto_now_add=True)
    updated_at=models.DateField(auto_now=True)
    def __str__(self):
        return self.doing_business_as

class Business(models.Model):
    business_name = models.CharField(max_length=50)

我从这个stackoverflow问题中得到了这些帮助： Giving a model knowledge of a many-to-many related model in django

将相关对象作为上下文值添加回Django中的渲染视图

0 个答案: