反序列化从web api

时间:2016-07-25 17:07:58

标签: asp.net-mvc asp.net-web-api

客户端获取对web api方法的请求并获取一个对象作为响应问题是我无法取消此对象..

客户端方法,向web api发出get请求

HttpClient client = new HttpClient();
                client.BaseAddress = new Uri("http://localhost:57752");
                HttpResponseMessage response = client.GetAsync("api/Auth/Login/" + user.Username + "/" + user.Password).Result;
                JsonResult result = null;
                if (response.IsSuccessStatusCode)
                {
                    result = response.Content.ReadAsAsync<JsonResult>().Result;
                    JavaScriptSerializer json_serializer = new JavaScriptSerializer();
                    User validUser = json_serializer.Deserialize<User>(result.Data.ToString());//Throws Exp.
                }

我想简单地将这个从api返回的对象实例放到validUser ..

错误消息:

  

无法将“System.String”类型的对象转换为类型   'MongoDB.Bson.ObjectId'

这是模特:

public abstract class EntityBase
{
    [BsonId]
    public ObjectId Id { get; set; }
}

public class User : EntityBase
    {
        //public string _id { get; set; }
        [Required]
        [StringLength(100, ErrorMessage = "The {0} must be at least {2} characters long.", MinimumLength = 5)]
        [DataType(DataType.Text)]
        [Display(Name = "Username")]
        public string Username { get; set; }

        [Required]
        [StringLength(100, ErrorMessage = "The {0} must be at least {2} characters long.", MinimumLength = 6)]
        [DataType(DataType.Password)]
        [Display(Name = "Password")]
        public string Password { get; set; }

        public void EncryptPassword()
        {
            Password = Encrypter.Encode(this.Password);
        }

        [DataType(DataType.Password)]
        [Display(Name = "Confirm password")]
        [Compare("Password", ErrorMessage = "The password and confirmation password do not match.")]
        public string ConfirmPassword { get; set; }
    }

1 个答案:

答案 0 :(得分:2)

你没有告诉反序列化器反序列化的内容。此

User validUser = (User)json_serializer.DeserializeObject(result.Data.ToString());

反序列化为一个对象,然后尝试将该对象强制转换为User,这将失败。您需要使用通用方法:

User validUser = json_serializer.Deserialize<User>(result.Data.ToString());

如果JSON名称和类名称/结构不同Changing property names for serializing,则完全有可能需要做更多的工作。