Question

我需要使用多个查询并将它们作为格式化的xml发送出去以用于as3目的。

当我只使用一个查询时，一切正常。

多查询操作时问题就开始了。

现在，当隐藏// XML标题时，我在屏幕上打印出一个结构，看起来很不错。

但是当标题启用时，没有任何作用！

请查看我的代码：

<?php   
$dbHost = "localhost";
$dbUser = "root";
$dbPass = "";
$dbName = "test";
$dbTable = "pizzaroma";

$mysqli = mysqli_connect($dbHost, $dbUser, $dbPass, $dbName);
if ($mysqli->connect_errno)
echo "la conection ha fallado: ".$mysqli->connect_errno;

$query = "SELECT * FROM ".$dbTable." WHERE cat='pizza' AND act='1'  ORDER BY ID ASC; ";
$query .= "SELECT * FROM ".$dbTable." WHERE cat='pasta' AND act='1'  ORDER BY ID ASC; ";    

if ($mysqli->multi_query($query)) {
     // header("Content-type: text/xml");
      echo "<?xml version='1.0' encoding='UTF-8'?>";
      echo "<pics>";
do { 
    echo "<theme name='temporaly'>";
    if ($result = $mysqli->store_result()) {

         while ($row = $result->fetch_assoc()) {

           echo "<pic name='".$row['NAME']."'  desc='".$row['DESCES']."' price='".$row['PRICE']."'/>";
           echo "</pic>";
        }
        $result->free();
    }
         echo "</theme>";
    if ($mysqli->more_results()) {          
    }

    } 
    while ($mysqli->next_result());  
        echo "</pics>";
}

    $mysqli->close();
    ?>

Answer 1

早些时候我正在使用“echo”，...现在我把“printf”放在那里，但是只有一些线，我不确定这是不是原因..但现在有效。它扔给我了

“严格标准：mysqli_next_result（）：没有下一个结果集。请调用mysqli_more_results（）/ mysqli :: more_results（）来检查是否调用此函数/方法”所以寻求帮助我找到了这一行那里：

 do{} while(mysqli_more_results($db) && mysqli_next_result($db));

解决了xml错误的问题。

<?php


$dbHost = "localhost";
$dbUser = "root";
$dbPass = "";
$dbName = "test";
$dbTable = "pizzaroma";

$mysqli = mysqli_connect($dbHost, $dbUser, $dbPass, $dbName);
if ($mysqli->connect_errno)
echo "la conection ha fallado: ".$mysqli->connect_errno;

$query = "SELECT * FROM ".$dbTable." WHERE cat='pizza' AND act='1'  ORDER BY ID ASC; ";
$query .= "SELECT * FROM ".$dbTable." WHERE cat='pasta' AND act='1'  ORDER BY ID ASC; ";
$query .= "SELECT * FROM ".$dbTable." WHERE cat='carne' AND act='1'  ORDER BY ID ASC; ";


if ($mysqli->multi_query($query)) {
      header("Content-type: text/xml");
      printf( "<?xml version='1.0' encoding='UTF-8'?>");
      printf( "<pics>");
do { 
    printf( "<theme name='temporaly'>");
    if ($result = $mysqli->store_result()) {

         while ($row = $result->fetch_assoc()) {

           echo "<pic name='".$row['NAME']."'/>";

        }
        $result->free();
    }
         echo "</theme>";

    } 
    while (mysqli_more_results($mysqli) && mysqli_next_result($mysqli));

        echo "</pics>";
}

    $mysqli->close();
    ?>

后来我不得不序列化xml输出很简单：D

>> $i=1;   and ... do {printf( "<theme name='".$i++."'>");

但现在，..如何将输出serialID与包含类别名称的数组中的元素相关联。类似......

如果name =“1”则name =“firtsArrayChild”

任何想法？但我认为那是另一首问题的另一首歌！感谢

XML通过MySQL多查询格式错误

1 个答案: